What is the Velocity and Distance of a Block on an Incline?

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SUMMARY

The discussion focuses on calculating the velocity and distance of a block sliding down a frictionless incline at an angle of θ = 50.0°. The block, with a mass of m = 2.00 kg, is released from a height of h = 0.300 m. The correct approach involves using kinematic equations or conservation of energy principles to determine the block's velocity as it leaves the incline and the distance it travels before hitting the floor. The initial calculations presented by the user were incorrect due to the misuse of equations and misunderstanding of the physics involved.

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Homework Statement


A block of mass m = 2.00 kg is released from rest at h = 0.300 m from the surface of a table, at the top of a θ = 50.0° incline as shown below. The frictionless incline is fixed on a table of height H = 2.00 m.

http://www.webassign.net/pse/p5-62.gif"

(b) What is the velocity of the block as it leaves the incline?


(c) How far from the table will the block hit the floor?


(d) How much time has elapsed between when the block is released and when it hits the floor?


The Attempt at a Solution



b. ax= 7.51m/s2
Hypothenuse: 0.357m
time to travel 0.357m:
d= volt +1/2at2
t=[tex]\sqrt{2da}[/tex]
t= 0.308s

Vx=Vxi + at
Vx= (7.51)(0.308)= 2.31 m/s
This was the wrong answer. I thought that finding the velocity at the time at which the block travels the hypothenus would give the correct velocity.

c. Since my velocity is wrong I can't solve for c or d.

c.
 
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Welcome to PF!

Hi xjasonx1! Welcome to PF! :wink:
xjasonx1 said:
Hypothenuse: 0.357m

Nooo … I think you've used tan instead of … ? :smile:

(and why have you used two equations? … there's a single constant acceleration equation that will do the trick … or you could even use conservation of energy!)
 
thanks tim!
 

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