What is the Velocity and Energy of a Child on a Swing?

  • Thread starter Thread starter physicsquest
  • Start date Start date
  • Tags Tags
    Swing Velocity
AI Thread Summary
To determine the child's speed at the lowest position of a swing, the potential energy at the initial height, calculated using trigonometry, is converted to kinetic energy at the bottom. The child, weighing 25.0 kg and swinging from a height determined by a 30-degree angle, can have their speed found using energy conservation principles. For the second part of the problem, the mechanical energy lost due to friction can be calculated by comparing the expected kinetic energy without friction to the actual kinetic energy at the lowest point. The actual speed of 2.00 m/s indicates energy loss, which can be quantified without needing the friction coefficient. Understanding these energy transformations is crucial for solving the problem effectively.
physicsquest
Messages
15
Reaction score
0

Homework Statement


A 25.0kg child on a 2.00m long swing is released from rest when the ropes of the swing make an angle of 30 degrees with the vertical. (a) Neglecting friction, find the child's speed at the lowest position. (b) If the actual speed of the child at the lowest position is 2.00 m/s, what is the mechanical energy lost due to friction?


Homework Equations


(1/2)mvf^2 - (1/2)mvi^2


The Attempt at a Solution


Do I need to use an energy equation to solve for velocity?
 
Physics news on Phys.org
Yep energy is a good idea :) Start by finding the potential energy of the system at rest. You know its at 30 degrees and its 2m long so by using simple trig you can find h, the height. With conservation of energy you know the bottom of the swing, its all kinetic energy so the potential energy at rest is equal to the kinetic energy. The 2nd part is pretty simple but please respond if its not clear to you.
 
I don't understand how to solve the 2nd part without given the coefficient of friction.
 
You don't actually need to know k since you already know the velocity of the kid at the bottom with friction involved. You also know the kinetic energy of the kid at the bottom without friction.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top