What is the velocity of a falling object with air resistance?

AI Thread Summary
The discussion focuses on calculating the velocity and angular velocity of a falling object, specifically a Samara seed, under the influence of air resistance. Key variables include the object's surface area, weight, drag coefficient, and the angle of inclination. The concept of terminal velocity is introduced, where the forces of lift and drag balance the force of gravity during steady descent. Participants explore the relationship between vertical velocity, height, and the time taken to fall, as well as how to determine the pitch angle of the helix created by the object's rotation. The challenge lies in accurately defining the radius of the helix and calculating the angular velocity based on the terminal velocity and pitch angle.
Antony Jose
Messages
6
Reaction score
0

Homework Statement


I am trying to develop simulation for a falling object subject to air resistance. Object is similar to Samara seed. object is considered to be under steady vertical descend.
know variable :
surface area of object (A)
weight of object (W)
cd: drag coefficient
object rotates while falling.
length from center of rotation to tip of the object (L)
inclines at an angle beta (β)
Swept disk radius (r) = L*cos(β)

Homework Equations


terminal velocity(Vs)= √[(2*W)/(cd*ρ*A)
Disk loading= W/A=ρ(Vs2-Vf2)/2

The Attempt at a Solution


I am stuck in this position and don't know how to approach the problem from here. want to know how to calculate the velocity of object and angular velocity of the tip of the object.
 
Physics news on Phys.org
I can't help with the aerodynamics but...

Antony Jose said:
object is considered to be under steady vertical descend.

If it's descending at constant velocity then at that velocity the vertical force upwards (caused by a combination of lift and drag) is equal to the force due to gravity downwards.
 
  • Like
Likes Antony Jose
thanks for the replies.
I had some more doubt. Like how to draw the helix created by the object if it start rotating 1 meter above the ground.
given that we know the velocity of fall, angular velocity of rotation and radius of helix.
 
If we assume that the seed very quickly reaches terminal velocity then that's solvable...

The vertical velocity (v) and the height (h) give you the time it takes to fall (t)...

t = h/v

Then the time (t) and angular velocity (ω) gives you the number of revolutions (n) it makes before hitting the ground..

n = ωt/2π (Note I had to edit this line)

Then the height (h) and the number of revolutions (n) gives you the pitch of the helix (p) in meters (p = the distance it falls per revolution)..

p = h/n

I'm not sure how you define the radius of the helix? I think seeds with a single wing rotate about a point on the wing near the seed head. So the seed and wing tip move in a helix (different radii) but the centre of rotation descends in a straight line (ignoring wind).
 
CWatters said:
If we assume that the seed very quickly reaches terminal velocity then that's solvable...

The vertical velocity (v) and the height (h) give you the time it takes to fall (t)...

t = h/v

Then the time (t) and angular velocity (ω) gives you the number of revolutions (n) it makes before hitting the ground..

n = ωt/2π (Note I had to edit this line)

Then the height (h) and the number of revolutions (n) gives you the pitch of the helix (p) in meters (p = the distance it falls per revolution)..

p = h/n

I'm not sure how you define the radius of the helix? I think seeds with a single wing rotate about a point on the wing near the seed head. So the seed and wing tip move in a helix (different radii) but the centre of rotation descends in a straight line (ignoring wind).
thank you for the help.
center of rotation can be found by find center of mass (C.M). Most of the seed have this as center of rotation.
 
Can you help me with finding the angular velocity of the object.
I took angular velocity as terminal velocty (vtrmnl)*sin(Θ)/radius, since no other force is acting on the object. [Θ is the angle of attack]
But I think there is some thing wron.
 
Antony Jose said:
I took angular velocity as terminal velocty (vtrmnl)*sin(Θ)/radius,

I make it

Angular velocity (Rads/s) = Vtrmnl / (Radius * Tan(Θ))

Seed fall.png


In one revolution it falls a distance h so

Tan(θ) = h/circumference
so
h = Tan(θ) * 2πR

The time for one revolution is t..

t = h/Vtermnl
t = (Tan(θ) * 2πR)/Vtermnl

Angular Velocity = angle/time
= 2π/t
= 2π/((Tan(θ) * 2πR)/Vtermnl)
= Vtermnl/(Radius * Tan(Θ))
 
I should add that in my post above the angle θ is the pitch angle of the helix (not the aerodynamic angle of attack). I don't think you can easily calculate the angular velocity from the aerodynamic pitch.
 
  • #10
CWatters said:
I should add that in my post above the angle θ is the pitch angle of the helix (not the aerodynamic angle of attack). I don't think you can easily calculate the angular velocity from the aerodynamic pitch.
How to find pitch angle?
I think we can find it using h and circumference. Using Pythagoras theorm.
 
Last edited:
  • #11
Correct although you don't need Pythagoras...

The pitch angle of the helix (distance descended per revolution) = Tan-1(h/circumference)

But note that this is not the same as the aerodynamic pitch.
 
  • #12
CWatters said:
Correct although you don't need Pythagoras...

The pitch angle of the helix (distance descended per revolution) = Tan-1(h/circumference)

But note that this is not the same as the aerodynamic pitch.

problem in this is that i couldn't find 'h'
CWatters said:
In one revolution it falls a distance h
.
 
Back
Top