What is the wavelength of light used in Young's double-slit experiment?

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In Young's double-slit experiment, a student measures the distance between the first and seventh nodal lines as 6.0 cm, with the screen 3.0 m from the slits and a slit separation of 2.2 x 10^2 nanometers. There is confusion regarding the conversion of the slit separation, with a suggestion that it should be 2.2 x 10^-4 meters instead of 2.2 x 10^-7. The discussion highlights that the slit separation value is critical for determining the wavelength of light, as a significant change could affect whether the wavelength falls within the visible spectrum. The conversation emphasizes the importance of accurate measurements and conversions in calculating the wavelength of light used in the experiment. Accurate calculations are essential for confirming that the light used qualifies as visible light.
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Homework Statement


A student performing Young's experiment with a single-colour source finds the
distance between the first and the seventh nodal lines to be 6.0 cm. The screen
is located 3.0 m from the two slits. The slit separation is 2.2 x 10^2 nanometres. Calculate
the wavelength of the light.

Homework Equations


x/L = wavelength/ d

The Attempt at a Solution


I found a solution online and they made the distance 2.2 x 10^-4 metres instead of 2.2 x 10^-7 if you do the conversion. I think they multiplied by something but i don't know why they would need to.
 
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The slit separation of 2.2 x 10^2 nanometres does not make any sense.
 
Dr. Courtney said:
The slit separation of 2.2 x 10^2 nanometres does not make any sense.
Why not? If you are referring to the practical limitation, we already have technology to fabricate sub-micro structure with a very good precision.
Hannahj1 said:
I found a solution online and they made the distance 2.2 x 10^-4 metres instead of 2.2 x 10^-7 if you do the conversion. I think they multiplied by something but i don't know why they would need to.
What number did you get using the original value of slit separation? I believe the number you got won't qualify to being called "light". Changing the slit separation by three orders of magnitude will make the wavelength lies in the visible region, which is in conform with the calling of the illuminating EM wave as light.
 
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