What is the weight that will balance the object Q?

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To maintain balance for the tower crane, the weight Q must be calculated based on two scenarios: full load and no load. In the full load scenario, the equation shows that the minimum weight Q must counterbalance the combined forces of the rack weight P and the load W. Conversely, in the no load scenario, the maximum weight Q must also counterbalance the rack weight P. The calculations reveal the critical weights required for Q to ensure stability under varying load conditions. Understanding these weight requirements is essential for safe crane operation.
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Here is diagram for Tower Crane.
BlSChqD.jpg

The Rack weight P=700kN, and the maximum load capacity for this crane is W=200kN. The long beam length is 12 metres, and the balance object weighs Q. The short beam length is 6 metres. What is the weight of Q to keep the crane's balance at all situation?
 

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Why should it be like that?
There are 2 situations
Full load, W=200 kN. let ##Q_{min}## stands for the minimum weight requirement of Q.

$$\sum m_B(F)=0, (6+2)Q_{min} + 2P - (12-2) W=0, N_A=0$$

No load, W=0 kN. let ##Q_{max}## stands for the maximum weight requirement of Q

$$\sum m_A(F)=0, (6-2)Q_{max} - 2P =0, N_B=0$$
 
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