What is the work done against the spring force in joules?

AI Thread Summary
To calculate the work done against the spring force when a 75 g mass stretches a spring from 4.0 cm to 7.0 cm and is then pulled an additional 10 cm, the spring constant (k) is determined to be 24.5 N/m. The total extension (x) is 0.13 m, which is used in the work formula W = 1/2 k x^2. The correct calculation yields a work done of 0.21 J. Some participants reported different results, with one stating 0.1962 J, but the consensus confirms 0.21 J as the accurate answer. Understanding the conversion of units and proper application of the spring force formula is crucial for solving this problem.
smile97
Messages
1
Reaction score
0
so i have tried this problem fifty million times and i can't get the right answer. hopefully someone can help. when a 75 g mass is suspended from a vertical spring, the spring is stretched from a length of 4.0 cm to a length of 7.0 cm. If the mass is then pulled downward an additional 10 cm, what is the total work done against the spring force in joules? i converted grams to kilograms and cm to m and used the equation f=kx and then plugged those numbers into w=1/2kx^2. i can't get the correct answer of 0.21 J. please help
 
Physics news on Phys.org
unfortunately, i get 0.1962 J; a wrong one .
 
i get the correct answer of 0.21J

k=24.5
x=0.13

plug them in and out pops the answer
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Spring constant formlula for Force and Work Done
Replies
12
Views
2K
Distribution of Energy when work is done on a system of 2 masses connected by a spring
Replies
17
Views
1K
Work done by a force on a spring
Replies
7
Views
1K
Work done pushing a spring from the side
Replies
9
Views
2K
Difficulty in deciding when to apply work energy theorem
Replies
2
Views
1K
Problem of spring block system: force vs conservation of energy
Replies
20
Views
3K
To find the work done in extending a spring
Replies
3
Views
1K
Work Done By a Spring's Restoring Force
Replies
4
Views
1K
Problem with when to use Force and Energy. What compresses spring/
Replies
3
Views
1K
Shm , calculation of amplitude of spring mass system
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top