What is the work done by an ideal gas in an isobaric process?

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In an isobaric process, the work done by an ideal gas can be calculated using the formula W = p(V2 - V1). For a gas heated from 27°C to 107°C at constant pressure, the calculation involves the ideal gas law. The initial attempt yielded a work value of 1300 J, but the correct answer, as per the textbook, is 1330 J. The discrepancy was resolved by using the equation W = nRΔT, which aligns with the textbook solution. Accurate calculations are essential for obtaining the correct work done in thermodynamic processes.
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[SOLVED] Isobaric process

Hi, need some help with this.

I got to moles of an ideal gas that are heated at constant pressure from T=27 C to T=107C.

How do I calculate the work done by the gas?

I know that for a isobaric process the work is given by

W = p(V2-V1)

Thanks
 
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HINT: Ideal gas law

P.S. We have Homework & Coursework forums for textbook questions.
 
Oh, I'm sorry. Yeah, I tried W = nRT.

Came out with 1300 J, but the key book says 1330 J.
 
Using W = nR\Delta T, my answer agrees with your text. I would suggest you re-check your calculations.
 
There, it worked.
 

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