What is the Y-component of T1 and T2?

  • Thread starter Thread starter rickstarr93
  • Start date Start date
  • Tags Tags
    Mass Speaker
AI Thread Summary
The discussion revolves around calculating the y-components of tension in a problem involving a speaker hanging from wires. The tension in wire 1 is given as 35N, and the user attempts to find the mass of the speaker using the equation m = (T1y + T2y) / g. However, confusion arises regarding the need for both x and y components of the tensions, as the user initially only considered the y-component. Participants emphasize the importance of drawing a free body diagram and correctly applying trigonometric functions to resolve the tensions into their components. Ultimately, the user is advised to clarify their understanding of vector components to accurately solve the problem.
rickstarr93
Messages
3
Reaction score
0

Homework Statement


A speakerh angs from the ceiling by a pair of wires, as showin the diagram below. the tension in wire 1 is 35N. What is the mass of the speaker?
Given from the problem and picture.


Wire1=25 degrees
Wire2=55 degrees
Tension in wire1= 35N
Tension in wire2=18.02N

Homework Equations


F=ma
x=T1sin(x)-T2sin(x)


The Attempt at a Solution


This is what I got but didn't get full points becasue I am missing the Y component?

x=35sin(25)-T2sin(55)
T2=35sin(25)/sin55
T2=18.05

Then we used this equation
T1y+T2y-mg
0=T1y+t2y-m(9.8)
Rearange and plug in numbers:
35+18.05/9.8

m=5.41kg

She told me I am right all the way up to the last part (35+18.05/9.8) and was told I'm need the y-components..but I solved for it?

Thank you!
 
Physics news on Phys.org
You didn't use the y components.

You have m= (T1y+T2y)/g = (35+18.05)/9.8

i.e. T1y=35N

but are you not told that T1=35N ?
if T1y=35N as well then T1x=0N - does that make sense?
 
So i need to find my x-components of T2x and then have both sides equal to each other?
But if T1x=0n then that is not relative to the equation?
Sorry for the questions, I"m still a bit confused.
 
You need both x and y components.

Draw a free body diagram for the speaker.
Divide the forces (tensions) into components parallel and perpendicular to gravity (easiest approach).
The horizontal forces sum to zero.
The vertical forces sum to zero.

You should end up with two equations and two unknowns.

Note:
if T1x=0 then there is no x component: what direction must T1 be acting in?
Does that fit the description?
 
so I would have to do instead of sin, I have to use cos?

35cos(25)/cos(55)= 55.30
 
You should use your understanding of trigonometry and vectors to solve the problem.
In long answers, you should show your understanding by what you write.

What you wrote in post #5 reads like you have just randomly guessed that you need to change all the sines to cosines as if you have not understood anything that has been suggested before.

If you won't take suggestions, I cannot help you.
If you don't answer questions, I cannot help you.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top