What is their velocity just after the tackle?

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The discussion revolves around calculating the final velocity of two players after a perfectly inelastic tackle. A 90-kg fullback moving east at 5 m/s collides with a 95-kg opponent running north at 3 m/s. The initial momentum must be conserved in both the east-west and north-south directions separately. The correct final velocity is determined by calculating the components in each direction and then combining them to find the magnitude. The final answer is clarified to be 2.9 m/s, not 3.9 m/s, emphasizing the importance of vector analysis in momentum conservation.
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okay, more questions for me!

this really, really easy question is not working out for me!

A 90-kg fullback moving east with a speed of 5 m/s is tackled by a 95-kg opponent rnning north at 3m/s. what is their velocity just after the tackle?

Perfectly inelastic, right?

so (90)(5) + (95)(3) = (m1 + m2) Vf
So, according to this, Vf= 3.9 m/s but the book answer is 2.9 m/s. What am I doing wrong?
 
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Remember that momentum is a VECTOR QUANTITY. You have to consider momentum conservation in both the East-West (x) and North-South (y)directions seperately. That is,

p_{x, initial} = p_{x, final} \ \ \ \ \ p_{y, initial} = p_{y, final}

After you find what the final velocities in the x and y directions remember that the magnitude of the velocity is

v_{final} = \sqrt{v_{x, final}^2 + v_{y, final}^2}
 
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oooooohhhhh yeah. thanks! let's see if i can get the answer now...
 
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