What is the Limit of the Half Bracket Operator?

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The discussion centers around the limit of [theta] / theta as theta approaches 3 from the left, with confusion about the "half bracket operator." The term refers to the floor function, which rounds down to the nearest whole number. A participant points out a mix-up between the floor and ceiling functions, prompting clarification. The solution manual indicates the limit is 2/3, which aligns with the floor function's definition. Overall, the conversation clarifies the use of the half bracket operator in mathematical limits.
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Homework Statement



the limit of [theta] / theta

as theta goes to 3 from the left hand side

The brackets though, are only the bottom half of a bracket, like an L and the mirror image of an L around the theta. The solution manual shows the answer is 2/3. I'm really quite confused on what the half bracket operator could be. Thanks in advance.
 
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It's the floor function. It means that you round down to the closest whole number.

So for example floor(9.6) would be rounded down to 9.
 
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Uh, aren't ceil and floor different? You defined one and then used the other in your example. Sorry to nitpick. :)
 
Hehe, typo -- fixed
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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