What Minimum Kinetic Energy is Required for Electrons to See an Atom?

AI Thread Summary
To resolve an atom using an electron microscope, a resolution of approximately 1.00 x 10^-11m is necessary. The minimum kinetic energy required for electrons can be calculated using the kinetic energy equation Ek = 1/2 mv^2, where the mass of an electron is 9.11 x 10^-31kg. Additionally, the De Broglie wavelength must be considered to relate the electron's wavelength to its momentum. Understanding the relationship between kinetic energy, velocity, and wavelength is crucial for determining the required energy. This knowledge is essential for effectively utilizing electron microscopy to visualize atomic structures.
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Homework Statement


The resolving power of a microscope depends on the wavelength used. If one wishes to "see" an atom, a resolution of approximately 1.00 x 10^-11m would be required.
a) If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons?


Homework Equations


Ek = 1/2 mv^2 (kinetic energy equation)
electron mass 9.11 x 10^-31kg
c = wavelength x frequency


The Attempt at a Solution


using the kinetic energy equation, I have 2 variables to consider. velocity (v) and kinetic energy (Ek) and how does wavelength fit into the question?
 
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aquabum619 said:

Homework Statement


The resolving power of a microscope depends on the wavelength used. If one wishes to "see" an atom, a resolution of approximately 1.00 x 10^-11m would be required.
a) If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons?


Homework Equations


Ek = 1/2 mv^2 (kinetic energy equation)
electron mass 9.11 x 10^-31kg
c = wavelength x frequency


The Attempt at a Solution


using the kinetic energy equation, I have 2 variables to consider. velocity (v) and kinetic energy (Ek) and how does wavelength fit into the question?
You have to use the De Broglie wavelength for the electron.

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