What particular integral should I use for SODE cosh2x

  • Thread starter Thread starter thomas49th
  • Start date Start date
  • Tags Tags
    Integral
thomas49th
Messages
645
Reaction score
0

Homework Statement


Hi, I've been asked to find the solution of y'' + 6y' + 8y = 12cosh2x

Homework Equations


The Attempt at a Solution



Well the complmentry function is Ae^-2x + Be^-4x

This creates a problem when trying our PI because we cannot try Ccosh2x and Dsinh2x because the hyperbolic functions contain e^-2x, which appears in our CF. Apparently I should try a PI of Ee^2x + (F+Gx)e^-2x, but I cannot see where on Earth this comes from? Why can't I try Ee^2x + Fxe^-2x. It must be simple :\

Thanks
 
Last edited:
Physics news on Phys.org
hi thomas49th! :wink:
thomas49th said:
This creates a problem when trying our PI because we cannot try Ccosh2x and Dsinh2x because the hyperbolic functions contain e^-2x, which appears in our CF. Apparently I should try a PI of Ee^2x + (F+Gx)e^-2x, but I cannot see where on Earth this comes from? Why can't I try Ee^2x + Fxe^-2x. It must be simple :\

yes, i think you're right :smile:

if Ee2x + (F+Gx)e-2x is a PI, then so is Ee2x + Gxe-2x

any solution is a PI ! :rolleyes:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top