What percentage of non-fatal accidents are caused by drivers who do not text?

AI Thread Summary
The discussion focuses on calculating the percentage of non-fatal accidents caused by drivers who do not text. It establishes that 40% of fatal accidents involve texting drivers, with only 1% of all accidents being fatal. Out of 200 accidents attributed to texting drivers, 4 are fatal, leaving 196 non-fatal accidents. The conversation highlights the distinction between different probability statements and their interpretations, particularly P(T|F) versus P(F|T). Ultimately, the analysis aims to clarify the correct approach to finding the desired percentage of non-fatal accidents.
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Homework Statement




A study of texting and driving has found that 40% of all fatal auto accidents
are attributed to texting drivers, 1% of all auto accidents are fatal, and
drivers who text while driving are responsible for 20% of all accidents. Find
the percentage of non-fatal accidents caused by drivers who do not text.

Homework Equations





The Attempt at a Solution



Let T denote texting while driving and let F denote fatal accidents.

P(F|T) = .40
P(F) = .01
P(T) = .2

I guess we are trying to find
p(F^{c}|T^{c}
= (p(F^{c}\bigcap T^{c}) / p(T^{c}

We know p(F|T) = p(F\bigcapT) / p(T) = 0.4 => p(F\bigcapT) = 0.08

Also p(F^{c} \bigcapT^{c}) = 1 - p(F\bigcupT)

p(F\bigcupT) = p(F) + p(T) - p(F \bigcapT) = .01 + .2 - .08 = .13

I am going to stop here because when I start plugging in everything I have I wind up with the wrong answer. Is ther an assumption I have wrong or have interpreted, as usual, the problem wrong?
 
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P(F|T) = .40
That would be "For texting drivers, 40% of all accidents are fatal", which does not match the problem statement.
 
So would it be p(F\bigcapT) = .40?


You got any hints?
 
Last edited:
DotKite said:
So would it be p(F\bigcapT) = .40?


You got any hints?

Now that reads "in 40% of all accidents the accident was fatal and the driver was texting". Still not what you want, given the probability of a fatal accident is only 0.01. Try again. Read these probability statement back in english. Here's a big hint. What does P(T|F) mean? State it in english.
 
P(T|F) reads the probability of an accident being caused by texting, given that it was fatal?
 
DotKite said:
P(T|F) reads the probability of an accident being caused by texting, given that it was fatal?

Ok, but, you should read it a little more literally. Nobody said anything about texting being the cause. It is just the probability that driver was texting given the accident was fatal. Now what's the value of that given the problem statement?
 
0.4?
 
Imagine 1000 accidents. "1% of all auto accidents are fatal" so there are 10 fatal accidents. "40% of all fatal auto accidents are attributed to texting drivers" so 4 of those fatal accidents are attributable to texting. "drivers who text while driving are responsible for 20% of all accidents" so 200 accidents are attributable to drivers who text.

That is, out of 200 accidents attributable to drivers who text, 4 of them are fatal and 16 are not fatal.
 
DotKite said:
0.4?

Yes, there's a big difference between P(T|F) and P(F|T). You might want to take another look at the expression you wrote for what you are trying to find.
 
  • #10
HallsofIvy said:
Imagine 1000 accidents. "1% of all auto accidents are fatal" so there are 10 fatal accidents. "40% of all fatal auto accidents are attributed to texting drivers" so 4 of those fatal accidents are attributable to texting. "drivers who text while driving are responsible for 20% of all accidents" so 200 accidents are attributable to drivers who text.

That is, out of 200 accidents attributable to drivers who text, 4 of them are fatal and 16 are not fatal.
Typo (?):
... and 196 are not fatal.
 
  • #11
haruspex said:
Typo (?):
... and 196 are not fatal.
Yes, thanks. Unfortunately, I can no longer edit it so I cannot pretend I didn't make that blunder!
 

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