Whats the best way to factor this

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To factor the expression 2cos^2(θ) + cos(θ) - 1, substitute x = cos(θ), resulting in the quadratic 2x^2 + x - 1. The factors can be determined as (2x - 1)(x + 1), which corresponds to the original expression when substituting back. Understanding the signs and coefficients is crucial for correct factorization. The final answer is achieved by replacing x with cos(θ), yielding (2cos(θ) - 1)(cos(θ) + 1). This method effectively demonstrates the process of factoring quadratic expressions involving trigonometric functions.
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Homework Statement



2cos^2(θ) + cos(θ) - 1

Homework Equations



2cos^2(θ) + cos(θ) - 1

The Attempt at a Solution



the answer is (2cos(θ)-1)(cos(θ)+1)

How do I factor this to give me that answer?
 
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Do a substitution, x = cos(theta)

Now you have 2x^2 + x -1.

You know the signs of the factors must be a plus and a minus, so ( + ) ( - ) the two on your x squared let's you know that you need a two x. And the 1 tells you both end digits must be 1. (2x-1) (x +1) is the only combination that works to leave you with one quantity of positive x.
 
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Here's an outline of the solution: As pointed out by Student100 the substitution ##\cos\theta\leadsto x## produces a quadratic, and if you know the roots of a quadratic -- say ##ax^2+bx+c## with roots ##r_1,r_2## if any -- then you can factor it as ##a(x-r_1)(x-r_2)##. The only step that remains is to “undo” the substitution by replacing ##x## with the original ##\cos\theta##. I hope you can achieve all of those steps to find your desired answer. ;-)
 
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