Wheastone Bridge Homework: Compute i1 and i2

  • Thread starter Thread starter kexanie
  • Start date Start date
  • Tags Tags
    Bridge
AI Thread Summary
In the discussion about computing currents i1 and i2 in a Wheatstone Bridge circuit, it is established that i2 equals 0 and i1 is calculated as 20/9 A due to the equal ratios of resistances. The question arises regarding the non-equivalence of the circuit in Figure b) to the Wheatstone Bridge in Figure a). It is noted that the current through the vertical wire connecting the parallel resistances differs between the two circuits. The application of Nodal Law is suggested to analyze the currents in both configurations. Understanding these differences is crucial for accurate circuit analysis.
kexanie
Messages
11
Reaction score
0

Homework Statement


Compute i1 and i2 in Figure a). R3 = R4 = 6Ω, and R5 = R6 = 12Ω.

Homework Equations



KVL and KCL

The Attempt at a Solution



Since R3 / R5 = R4 / R6 , it's a Wheastone Bridge and i2 = 0, and i1 = \frac{20}{9} A.

But my question is, why circuit in Figure b) is not equivalent to circuit in Figure a) when a) is a Wheastone Bridge?
 

Attachments

  • Diagram1.png
    Diagram1.png
    13.1 KB · Views: 528
Last edited:
Physics news on Phys.org
kexanie said:

Homework Statement


Compute i1 and i2 in Figure a). R3 = R4 = 6Ω, and R5 = R6 = 12Ω.

Homework Equations



KVL and KCL

The Attempt at a Solution



Since R3 / R5 = R4 / R6 , it's a Wheastone Bridge and i2 = 0, and i1 = \frac{20}{9} A.

But my question is, why circuit in Figure b) is not equivalent to circuit in Figure a) when a) is a Wheastone Bridge?


The current through the vertical wire between the two pairs of parallel resistances is not equal to I2. Consider the Nodal Law. What is I2 in a) and what is it in b). Are they identical?

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top