Undergrad When and How to Solve ODEs: Clarity for Confused Students

Click For Summary
Understanding when to use specific methods for solving ordinary differential equations (ODEs) is crucial. The exponential function y=e^mx is appropriate for ODEs with constant coefficients, while the polynomial function y=x^m is suitable for Cauchy-Euler equations. The derivatives of e^ax retain the same form, making them effective for linear differential equations with constant coefficients. In contrast, the derivatives of x^a yield different powers, which aligns with equations that have polynomial coefficients. Clarity on these distinctions aids in selecting the correct approach for solving ODEs.
ABearon
Messages
5
Reaction score
1
TL;DR
when to use e^mx and x^m
I know how to solve ODEs using both methods. The problem I'm having is knowing when to use one and not the other. If someone could help clarify this for me. I can't find the correct section in my textbook.
 
Physics news on Phys.org
Hello ABearon, :welcome: !

Bit hard to answer without examples. Perhaps you can provide an example for yourself by going the other way: try to compose an exercise where ##x^m## is a useful trial function and another example where ##e^{mx}## is a good choice. Not too hard: simply differentiate and see what kind of DE you can make form the result !
 
BvU said:
Hello ABearon, :welcome: !

Bit hard to answer without examples. Perhaps you can provide an example for yourself by going the other way: try to compose an exercise where ##x^m## is a useful trial function and another example where ##e^{mx}## is a good choice. Not too hard: simply differentiate and see what kind of DE you can make form the result !
I think i figured it out. We're supposed to use y=e^mx when the ode has constant coefficients (a, b, c) and y=x^m for Cauchy-Euler equations, which are ODEs but the terms have have a-sub-n(x^n)(d^n y/dx^n)
 
  • Like
Likes BvU
The derivatives of e^{ax} are all of the form e^{ax} again. That is why they are solutions to linear differential equations with constant coefficients. The derivatives of x^a are of the form x^b with b< a. That is why the are solutions to linear differential equations with powers of x as coefficients.
 
  • Like
Likes atyy and ABearon

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
1K
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K