When can you assume dynamic equilibrium?

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SUMMARY

The discussion focuses on calculating the normal force acting on a 23 kg child sliding down a 38° inclined slide. The solution involves applying the equation ƩFy = (Fk)y + ny + wy, where Fk represents kinetic friction, n is the normal force, and w is the weight. The calculated normal force is approximately 180 N, confirming that the child is in dynamic equilibrium with no net acceleration along the Y-axis, despite moving down the slide. The realization that the incline affects the acceleration dynamics is crucial for understanding the problem.

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  • Understanding of Newton's laws of motion
  • Knowledge of forces acting on inclined planes
  • Familiarity with trigonometric functions, specifically cosine
  • Basic principles of dynamic equilibrium
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  • Study the effects of friction on inclined planes
  • Learn about vector decomposition of forces
  • Explore the concept of static vs. dynamic equilibrium
  • Investigate the role of angles in force calculations on inclines
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of dynamic equilibrium in real-world scenarios.

Coop
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SOLVED

Homework Statement



A 23 kg child goes down a straight slide inclined 38∘ above horizontal. The child is acted on by his weight, the normal force from the slide, and kinetic friction. Find the magnitude of the normal force.

Homework Equations



cos(theta)=adjacent/hypotenuse

The Attempt at a Solution



I have the answer:

ƩFy=(Fk)y + ny + wy

Where Fk is kinetic friction, n is normal force and w is weight

ƩFy=0+ny+(-178 N) <- 23 kg * 9.81 m/s^2 = 226 N, 226N * cos(38) = 178 N

Now I know the answer is 180 N (rounded), but for that to be true, ƩFy would have to equal 0, which means that the Fnet would equal 0, which would mean that the kid is in dynamic equilibrium and has an acceleration equal to 0. But why is this true? Wouldn't the kid be accelerating while going down the slide?

Thanks,
Coop
 
Last edited:
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I figured it out. I forgot to to remember that the kid is on an incline, but how I drew it is having the X-axis horizontal, therefore there will not be any acceleration along the Y-axis.
 

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