When can you assume dynamic equilibrium?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
Coop
Messages
40
Reaction score
0
SOLVED

Homework Statement



A 23 kg child goes down a straight slide inclined 38∘ above horizontal. The child is acted on by his weight, the normal force from the slide, and kinetic friction. Find the magnitude of the normal force.

Homework Equations



cos(theta)=adjacent/hypotenuse

The Attempt at a Solution



I have the answer:

ƩFy=(Fk)y + ny + wy

Where Fk is kinetic friction, n is normal force and w is weight

ƩFy=0+ny+(-178 N) <- 23 kg * 9.81 m/s^2 = 226 N, 226N * cos(38) = 178 N

Now I know the answer is 180 N (rounded), but for that to be true, ƩFy would have to equal 0, which means that the Fnet would equal 0, which would mean that the kid is in dynamic equilibrium and has an acceleration equal to 0. But why is this true? Wouldn't the kid be accelerating while going down the slide?

Thanks,
Coop
 
Last edited:
Physics news on Phys.org
I figured it out. I forgot to to remember that the kid is on an incline, but how I drew it is having the X-axis horizontal, therefore there will not be any acceleration along the Y-axis.