When do the two balls pass each other in the annoying juggler problem?

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The discussion centers on the timing of two balls thrown by a juggler in a room with a 3 m ceiling. The first ball reaches the ceiling in 0.775 seconds, and the second ball is thrown at that moment with the same initial velocity of 7.75 m/s. A participant mistakenly assumes the balls pass each other at 1.5 m, but this is incorrect. To find the correct time they pass each other, one must equate the height equations of both balls and solve for the time. The solution requires a proper application of quadratic equations rather than assumptions about their midpoint.
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a juggler performs in a room whose ceiling is 3 m above the level of his hands. he throws a ball vertically upward so that it JUST reaches the ceiling. he then throws a second ball upward with the same inital velocity, at the instant the first ball is at the ceiling. How long after the second ball is thrown do the two balls pass each other?

okay, so I've gotten that the intial velocity of the balls is 7.75 m/s and that the time required for a ball to hit the ceiling is 0.775 seconds. the answer sheet tells me this is right. so i thought that, considering the situation, the balls would pass each other halfway through their trips, at 1.5 m. so i solved the quadratic that gave me how long it would take the second ball to reach 1.5 m and i got 0.175 seconds. this is wrong. how come? if they don't pass each other halfway through their trips then when?

thanks in advance
 
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You're trying to solve for when they pass each other, you can't just guess (well you can but...) at 1.5m they pass. If you imagine the paths followed by the two balls and you want to find the point where they have the same height, use your quadratic equations for both balls by equating the height, then solve for the time.
 
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