When scientists use a log graph, do they actually convert x/y w/ log?

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When using log graphs, values are typically plotted directly without conversion to logarithmic scale, as the graph's scale accounts for this distortion. Log-log and semi-log graph paper can facilitate this process by preprinting logarithmic scales, allowing for accurate plotting without manual calculations. In modern practice, software tools like Excel can automatically adjust scales to logarithmic, simplifying the plotting process. Clarity in labeling what is being plotted is essential to avoid misunderstandings. Overall, the discussion emphasizes the importance of understanding the graphing method used rather than converting values to logarithmic form.
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Homework Statement


For example, a linear plot would with x and y values would just plot normally where x and y increases linearly from 0 to infinity.

When we use a log graph, do we just plug in x and y to a graph in which the x and y go from 0, 10, 100, 1000, or do we convert the numbers such as log(x) = new y and then plug it into a graph that goes from 0, 10, 100, 1000?


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I'm not sure what your question is. I know it used to be possible, and still may be, to get "semi-log" or "log-log" graph paper. The latter has both axes labeled such that the point labeled "2" is actually at distance "log(2)" from the origin (which is labeled "1"). The "semi-log" paper has one axis like that, the other a regular linear numbering. If you are using such paper, you mark them as they are labeled.
 
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hongiddong said:

Homework Statement


For example, a linear plot would with x and y values would just plot normally where x and y increases linearly from 0 to infinity.

When we use a log graph, do we just plug in x and y to a graph in which the x and y go from 0, 10, 100, 1000, or do we convert the numbers such as log(x) = new y and then plug it into a graph that goes from 0, 10, 100, 1000?

We do not convert the numbers to log(x) = new value.
We plot directly the initial values x without taking a log. The idea is that the scales on the graph paper are distorted in such a way that the log will be taken into account graphically.


The second option is to use *ordinary* graph paper and plot on it the calculated log values of the x.
 
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Thank you! I understand it now!
 
In the "good ol' times" when you would draw graphs by hand, you would typically have log-log paper with preprinted logarithmic scales. This would make it easy to draw your points in the correct places without having to compute the log. Nowadays most people would simply let a computer draw the graphs for them and it no longer matters much. I have seen examples in scientific papers of people plotting in log scale with logarithmic scales, in which case the values on the scales would not be converted, and of people plotting log10(x) in a linear scale (in which case this would be clearly stated). As long as you are clear about what is being plotted, there should be no possibility for misunderstanding.
 
HallsofIvy said:
I'm not sure what your question is. I know it used to be possible, and still may be, to get "semi-log" or "log-log" graph paper. The latter has both axes labeled such that the point labeled "2" is actually at distance "log(2)" from the origin (which is labeled "1"). The "semi-log" paper has one axis like that, the other a regular linear numbering. If you are using such paper, you mark them as they are labeled.

Probably most office supply stores would not carry log-log or semilog paper anymore, but university stationers might---I haven't checked. If not, there are numerous websites that have such paper downloadable and/or printable.
 
All the graphics packages, like excel and kaleidagraph, allow you to change the scale to logarithmic automatically, so you just plot x vs y, and then, from a drop down menu, switch to logarithmic scales with a click of your mouse.

Chet
 
Nowadays, there are sites with semilog and log-log paper as a jpeg which you can download and print off. FREE! :smile:
You get to choose how many cycles you need.

EDIT. So now I look back and see Ray Vickson already said as much.
 
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