When will the barrel become half empty?

AI Thread Summary
The discussion revolves around calculating the time it takes for a barrel filled with 200 liters of water to become half-empty through a 1 cm² hole at the bottom. The user is struggling to apply relevant equations, including Bernoulli's principle and Torricelli's law, and is unsure how to incorporate the hole's size into their calculations. They have attempted basic conversions and set up equations but are finding it difficult to derive a solution due to the variable velocity of the exiting water. A suggestion is made to correlate the sinking velocity of the liquid level with the velocity of the exiting water and to solve the resulting differential equation. The conversation emphasizes the need for a systematic approach to the problem using calculus.
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Homework Statement


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I'm not a native english speaker, so I apologize if my explanations are a bit awkward. I do not have a solution to this problem and I'd be grateful if someone could check this/help. I also have absolutely no idea how to even begin. Asked my colleagues, none of them know. I'm pretty desperate.

There's a barrel filled with water. The volume of water inside is V=200L. Its hight is 1m.
We decide to make a hole on the bottom of the barrel. The size of the hole is 1cm2.

How much time will it take for the barrel to become half-empty (when will the height drop to 1/2 of the initial height)?

Homework Equations


What I believe is relevant here is:

Applying Bernoulli's principle:
p1+qgh1+1/2qv1^2=p2+qgh2+1/2qv2^2

Toricelli (this is derived from Bernoulli's principle in this case from what I understand):
v=sqrt(2*g*h)

Continuity equation:
S1v1=s2v2

The Attempt at a Solution


I got used to solving problems that include manometers, tubes of different sizes etc., but with a simple problem like this, I'm not sure where to begin.

First I did basic conversions.

V=200*10-3m3
S=1*10-4m2

My first thought was writing down:

h1=1/2*h2

and proceed from there, but I didn't get anything useful, since none of the equations I've written down took the size of the small hole into consideration.

t=v*s would seem fine, but since velocity isn't constant, I need a differential equation, ending up with an integral I cannot solve nor does it seem like a way to solve this (please correct me if I'm wrong).

I tried writing down the Bernoulli equation I've written above and it just leads to v=sqrt(2gh). Again, I'm not getting anything. Tried S1*v1=S2*v2, but since v1 is close to zero, I can't get anything from this equation either.
 
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1) In a first step you have to correlate the sinking velocity of the liquid level (##dh/dt##), with the velocity of the exiting water (with Torricelli)
2) By separation of the variables ##h## and ##t## and integrating (which is quite easy to write down, but not that easy to do), you obtain an initial value problem, which you can solve by inserting the height of the level at ##t=0##

But I suggest you start with 1)
 
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