Where does the energy from Nuclear Fission comes from?

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SUMMARY

The energy released from nuclear fission, specifically in the fission of Uranium-235, is derived from the mass difference between the reactants and the products. The typical fission products include Barium-141 and Krypton-92, along with three neutrons. The mass difference, calculated as 0.186 amu, translates to an energy release of approximately 173 MeV, which aligns closely with the average energy output of 200 MeV for U-235 decay. Accurate calculations require attention to small mass differences, emphasizing the importance of precision in nuclear physics.

PREREQUISITES
  • Understanding of nuclear fission processes
  • Familiarity with mass-energy equivalence (E=mc²)
  • Basic knowledge of atomic structure, including protons and neutrons
  • Experience with energy calculations in nuclear reactions
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  • Explore detailed calculations of mass defect in nuclear reactions
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  • Learn about the applications of nuclear energy in power generation
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This discussion is beneficial for nuclear physicists, students studying nuclear engineering, and anyone interested in the principles of nuclear energy and fission processes.

Leronira
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Looking at the fission of Uranium 235, the typical end product will be Barium 141 and Krypton 92, and 3 neutrons.
From this, we can calculate the energy that the fission gives off, by taking the difference in mass of the product and "reactant", and use the equation of E=mc2.
But what i see from the above, there isn't any difference in mass. Or am I missing out something here? Someone enlighten me please. Thanks
 
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There is a difference in mass, just a very small one...for these calculations, you can not use the usual approximation that mass is just number of protons plus number of neutrons.
235.0439299-140.914411-91.926156-2(1.0086649)=.186amu

In energy this is equivalent to 173MeV which is around the 200MeV usually released by U-235 decay.
 
OHH...so i have to look all the way down to many decimal places inorder to see the difference in mass...ok..thanks a lot...=D
 

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