Which ball will hit the ground first?

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When two tennis balls are thrown horizontally from the same height, their horizontal velocities do not affect the time it takes for them to hit the ground. Both balls, regardless of their speeds of 10 m/s and 14 m/s, will fall at the same rate due to gravity. The time to reach the ground is determined solely by the height from which they are thrown and the acceleration due to gravity. If air resistance is neglected, both balls will hit the ground simultaneously. Thus, they will take the same amount of time to fall, confirming that horizontal motion does not influence vertical descent.
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What hits the ground first??

Homework Statement



If we simultaneously throw two tennis balls horizontally from the top of a building, one at 10 m/s and the other at 14 m/s. Neglecting the air resistance, which one will hit the ground first?

Homework Equations


i don't think we use equations, but we have to consider the speed of each ball and how they are thrown horizontally??


The Attempt at a Solution



I think the ball with 10 m/s should hit the ground first because it won't reach far and eventually fall vertically from the top of buliding ?? please help out??
 
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They both start with a vertical velocity of 0.

Horizontal velocity does not affect vertical velocity.
 


You could also use equations of projectile motion to confirm this.
 


Technically, the 10 m/s tennis ball will hit the ground first, but not for the reason you mentioned.

It's because the Earth is round! The ground where the 14 m/s tennis ball impacts is just a few microns lower, so that ball has further to fall!

Otherwise, assuming flat Earth, they'd both hit at the same time.
 


Yes, considering the Earth is flat, they both will hit at the same time.
The one with an initial speed of 10m/s will travel a less distance and the one with an initial velocity of 14m/s will travel more, but they will take the same time.
You can verify this with this equation:
For motion on the y-axis:- h=uyt - 1/2gt2

since 'uy' is zero, the equation simplifies to:-

h= -1/2gt2
or, t=sqrt of (2h/g)

Since 'h' and 'g' are same in the case of both the balls, the time taken by each to reach the ground will be equal.
 
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