Which Capacitor Value Removes Ripples from 50Hz 12V Pulsating DC?

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To effectively remove ripples from a 50Hz, 12V pulsating DC signal, the appropriate capacitor value can be calculated using the formula C = Q/V = (I * t)/V, where I is the load current, t is the discharge time (20ms for half-wave and 10ms for full-wave or bridge rectifiers), and V is the ripple voltage. The discharge time for a bridge rectifier is the same as for a full-wave rectifier, which is 10ms. Capacitors are preferred over inductors for filtering due to their ease of fabrication, lower cost, and ability to act as peak detectors, while inductors tend to be heavier, more expensive, and can produce audible hum. Additionally, capacitors help accommodate load variations, providing low impedance, unlike inductors which have a steady-current characteristic. Understanding these factors is crucial for effective ripple reduction in rectification circuits.
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Which value of capacitor should i use in rectification so as to remove the ripples from the pulsating d.c? Having 50 hz 12 volts ..any formula related with ripples and capacitance?
 
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You can use this equation

C = Q/V = ( I * t )/V

where
I - load current
t - discharge time 1/50Hz (20ms) for half wave rectifier and 1/100Hz (10ms) for full wave rectifier or 1/60Hz and 1/120Hz for countries with 60Hz mains.
V - capacitor ripple voltage
 
Oh thanks i'll use this formula let's c...
 
And what's the value of t for bridge rectifier? Same as full wave ?
 
neeraj kaira said:
And what's the value of t for bridge rectifier? Same as full wave ?
Yes, the same as for full wave.
t = 10ms
 
This kind of image usually helps to visualize what is going on...

http://macao.communications.museum/images/exhibits/2_16_0_12_eng.png
2_16_0_12_eng.png
 
Thanks and m one more ques please why we mostly use capacitor filter and inductor not ? Inductor also blocks high frequency waves...its only because capacitor is easy to fabricate in the circuits?
 
Inductors are comparatively heavy and expensive. They can hum audibly. Also, the capacitor input filter is a peak detector, whereas the inductor is an averaging filter so delivers a lower output voltage for the same transformer voltage input.

You'll still need a filter capacitor to accommdate load variations (to realize a low-impedance), because the inductor has a steady-current characteristic (a high impedance characteristic).
 
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Ok thanks :)
 
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