Which diameter of two core cable?

AI Thread Summary
The discussion focuses on determining the appropriate diameter of a two-core cable for a 5 kW solar PV system located 30 meters from control electronics, aiming to limit power loss to around 10%. The resistivity of copper is noted, and calculations are presented using a resistance table for copper wire. Specifically, 14 gauge copper wire is referenced, with a maximum rating of 5.9 amps and a resistance of 2.5 ohms per 1000 feet, leading to a calculated power loss of 12.5 watts for both conductors. The thread invites further input on the necessary cross-sectional area of the cable to achieve the desired efficiency. Overall, the discussion emphasizes the importance of selecting the right cable size to minimize losses in solar PV installations.
blimthepixie
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Hello all,

First time here and first time posting. Just like to say a quick hello before getting started...

Due to the rise of solar PV panels being installed before the Feed in Tariff was cut earlier this year (in the UK) I've been thinking about the cable losses that these incur.

Imagine a relatively small, 5 kW system with a peak power rating of 175W (and 5A). This array is 30m from the control electronics and is using 2-core cable. (Copper having a resistivity of 1.69 x 10^-6 m^3).

What cross sectional area of cable will be needed to keep power loss in the cable to around 10%?.

Thanks in advance for taking a look at this and if I've negated to mention anything important just let me know...
 
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Use this copper wire resistance table http://www.powerstream.com/Wire_Size.htm
For example, 14 Ga. copper wire is rated at 5.9 amps max, and has a resistance of 2.5 ohms per 1000 feet. So for 30 meters = 100 feet, the power loss is I2 R = 52·0 .25 = 6.25 watts.
 
Bob S said:
Use this copper wire resistance table http://www.powerstream.com/Wire_Size.htm
For example, 14 Ga. copper wire is rated at 5.9 amps max, and has a resistance of 2.5 ohms per 1000 feet. So for 30 meters = 100 feet, the power loss is I2 R = 52·0 .25 = 6.25 watts.
Sorry. This is for only one conductor. Two conductors represent 12.5 watts.
 
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