Which Electrons Belong to the Valence Orbitals?

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The discussion focuses on identifying the valence orbitals for three neutral atoms based on their electron configurations. For atom A, the valence orbitals are 2s and 2p; for atom B, they are 4p and 5s; and for atom C, the valence orbital is 4s. Participants confirm the correctness of these identifications, with a specific emphasis on reviewing atom B's configuration. The conversation also touches on determining which electrons have the highest principal quantum number, indicating a deeper exploration of electron configurations.
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Homework Statement



The electron configuration for three neutral atoms are as follows.

A.1s22s22p3
B.1s22s22p63s23p64s23d104p55s24d7
C.1s22s22p63s23p64s23d6

Indicate which are valence orbitals.

The Attempt at a Solution



A.2s22p3
B.4p54d7
C.4s2


Please check if i have this corrrect.
 
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Looks right to me man.
 
Look at B again.
Which electrons have the highest principal quantum number?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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