Kontilera said:
Lets say that we want to express the quarter of the unit circle that is positioned in the first quadrant as a sum of square waves. The arc length of this curve is one half pi. Although by just adding square waves it seems that the arc length for the generated curve always will give 2.
How do you get 2 for the arc length? For a quarter circle of radius 1, if I divide the interval [0, 1] into n equal subintervals, the total length of the horizontal tops of the waves is ##\frac {n - 1} n##, which approaches 1 as n grows large.
This is the same idea of why you can't approximate the length along a curve by a sum of horizontal pieces -- ##\int_a^b \sqrt{1 + (f'(x))^2} dx## gives the correct arc length, but ##\int_a^b 1 dx## just gives the length of the interval [a, b]. If you want to approximate the area within the quarter circle, rectanular subareas work just fine, but they don't work at all if you want to approximate the length along the quarter circle.
Kontilera said:
This means that although we expect our generated curve to converge to the original curve, some properties won't converge.
I don't think this is important. The point of Fourier series is to be able to approximate discontinuous functions such as square waves, sawtooth waves, and so on, with a series of continuous functions that are sums of sine and/or cosine functions of varying periods and amplitudes. All that is required is that the Fourier series function values agree with the function values of the discontinuous square wave, sawtooth wave, etc.
Kontilera said:
Could this be an argument that our square waves doesn't span the function space?
What function space? If you're talking about the function space of all continuous functions, then square waves aren't in that space, because they aren't continuous.