Which one has the higher enthelpy, the reactent or the product?

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SUMMARY

The discussion centers on the enthalpy comparison between 2Cl(g) and Cl2(g) in the reaction 2Cl(g) → Cl2(g) with a ΔH of -243.4 kJ. It is established that 2Cl(g) possesses a higher enthalpy than Cl2(g) under the specified conditions. The confusion arises from the misconception that reversing the reaction would yield the same enthalpy change in magnitude but opposite in sign. The key takeaway is that the enthalpy change reflects the energy released during the exothermic reaction, indicating that the products (Cl2) have lower energy than the reactants (2Cl).

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Lion214
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2Cl(g)→Cl2(g) ΔH = -243.4 KJ

Which has the higher enthalpy under these conditions, 2 Cl (g) or Cl2 (g)?





At first, I thought they would have the same change in enthalpy, because if I make it a reverse reaction, their magnitude will be the same. Then I realized that the signs would reverse, making the change of enthalpy for the product positive. Apparently that was not the answer, as 2 Cl(g) has a higher change in enthalpy. I'm posting this because I want to know why that is?
 
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Think in terms of the exo- and endothermic reaction. Where does the reaction heat come from?
 

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