Which presses surface by higher force

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The discussion revolves around the forces exerted by two trains, A and B, moving in opposite directions along the equator. The key question is whether the force F1 (train A) is greater than, equal to, or less than force F2 (train B). The analysis indicates that both trains exert the same force due to their identical mass and speed, but the conclusion drawn is that F1 is greater than F2. The participants suggest that using an inertial frame simplifies the problem and provides clarity. Overall, the consensus is that the forces are not equal, with F1 being greater.
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Homework Statement


A train "A" runs east to west and another train "B" of the same mass runs from west to east at the same speed along the equator."A" presses the track with a force F1 and "B" presses the track with a force F2
<a>F1>F2
<b>F1=F2
<c>F1<F2
<d>the information is insufficient to find the relation b/w F1 and F2

Homework Equations


When we view a motion from a rotating frame with constant angular velocity "w" , then a pseudo force = mw2r gets applied on the object in radially outward direction being viewed[where r is the distance of object from the axis].


The Attempt at a Solution


For both the trains . i am getting same value.
> mg - m(we)2R - F1 = (mv2)/R
> mg - m(we)2R - F2 = (mv2)/R
As for both the trains , mg will be toward Earth's center , pseudo force[as we see from frame of earth] radially outward .
But the answer is <a>.
Any guidance :)
Thanks in advance.
 
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hi vissh! :smile:

(have an omega: ω :wink:)
vissh said:
When we view a motion from a rotating frame with constant angular velocity "w" , then a pseudo force = mw2r gets applied on the object in radially outward direction being viewed[where r is the distance of object from the axis].

that pseudo force is the https://www.physicsforums.com/library.php?do=view_item&itemid=84"

(btw, it would be a lot easier to do this in a stationary frame! :rolleyes:)
 
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hi tiny-tim :D
Thanks got it now :) And yep using inertial frame gave a quick solution ^.^
 
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