Which Spring Oscillation Frequency is Correct?

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The discussion centers on the oscillation frequency of a spring when a mass is suspended vertically compared to when it is oscillating horizontally. The consensus is that the frequency remains unchanged regardless of the orientation, leading to the conclusion that option C is correct. Although two forces act on the mass in the vertical position, the frequency is determined solely by the spring constant (k) and mass (m), not the orientation. The equilibrium position shifts when the spring is vertical, but this does not affect the frequency. Ultimately, the frequency of the spring's oscillation is independent of its position.
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Homework Statement


mass of the body=m

Horizontally, the spring is deflected from its equilibrium position and then released, oscillated with a frequency f. Then, the same spring and the same body are suspended vertically, as in figure.

Which one is correct?

A) The frequency of movement of the spring, when the body is suspended vertically, doubled.

B) The frequency of movement of the spring, when the body is suspended vertically, reduced to half.

C) The frequency of movement of the spring, when the body is suspended vertically, remains the same.

D) The frequency of movement of the spring, when the body is suspended vertically, is not related to the period of the movement, when the spring oscillates horizontally.

Homework Equations





The Attempt at a Solution



I think is C) but I think that D) is also correct. Please help me
 

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Describe how you came to that conclusion.
 


I think is C) because the frequency is a characteristic of the oscillator.

I think that D) is also correct because we change the position of oscillator and in the second case there are 2 forces: grav force and elastic force, in the first case there is only elastic force.
 


It's true that when suspended vertically there are two forces to consider, but it still turns out that the frequency depends only on the ratio of k/m.

How does period relate to frequency?
 


f= 1/T

so is C) ?
 


JoanF said:
f= 1/T
Right.
so is C) ?
Yes, C is correct. D doesn't really make sense, since if the frequency is unchanged the period must also be unchanged.
 


so the in spite of in 2nd case there are 2 forces acting, that doesn't change anything, right?
 


JoanF said:
so the in spite of in 2nd case there are 2 forces acting, that doesn't change anything, right?
What changes is the length of the spring when the system is at its equilibrium point. In the horizontal case, the equilibrium position is when the spring is unstretched; but when vertical, the spring is stretched at equilibrium (by an amount = mg/k).

But that doesn't affect the choice of answer.
 


oh ok, now I understand

many thanks, really!
 
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