Which Water Tank Piston Requires More Force?

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The discussion centers on understanding the force required by two pistons in water tanks with different hose penetration heights. Both tanks are identical in size and water level, but one hose penetrates the tank at 3 feet above the chamber, while the other penetrates at 22 feet. The pressure exerted on each piston is determined by the height of the water column above it, following the principle of static pressure head (ρgh). The piston connected to the hose at 3 feet will require less force due to the lower pressure compared to the one at 22 feet, which experiences greater pressure from the higher water column. Thus, the piston at the higher penetration point will require more force to operate.
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It may be a simple question to you but I need help understanding head pressure and I need to set things up to ask it.

Assume two 4 ft diameter by 25 ft tall water tanks, both are equally filled to 23 ft. Both tanks have chambers of the same diameter as the tank attached below them. Each chamber has a piston and has 2 ft of water above their pistons. Both chambers have a 4 inch diameter hose going from their chambers and into the tanks. On one of them, the other end of the hose penetrates the tank at 3 feet above the chamber. On the other the hose penetrates the tank at 22 ft above the chamber.

My question is, which piston will require more force or is there any difference. I would also appreciate any explanation that you want to include.
 
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morfzcspls said:
Assume two 4 ft diameter by 25 ft tall water tanks, both equally filled to 23 ft. Both tanks have chambers of the same diameter as the tank attached below them. Each chamber a piston and has 2 ft of water above their pistons. Both chambers have a 4 inch diameter hose going from their chambers and into the tanks. On one of them, the other end of the hose is penetrates the tank at 3 feet above the chamber. On the other the hose is penetrates the tank at 22 ft above the chamber.
Ahh.. Can you show a simple diagram? :biggrin:
 
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The pressure head depends on the density and elevation of liquid (or gas) above a given point by virtue of ρgΔh, where ρ is the mean fluid density, g is the acceleration of gravity, and Δh is the height of the fluid above the point of interest. The higher the column of water, the greater the pressure at the base or lowest point.

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
 
I have added a diagram called Undrstnd hd.png in hopes of clarifying this question.
 

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Big fat blank. Please try again. Always use the 'preview' button to check how your material displays before you post.
 
Sorry for the problem with the picture I attached previously. I’m having an issue with the latest update of DraftSight not exporting DWG files. Several of the formerly possible file types (.png, .tif, .wmf, .emf) create the file but they are not visible. So it seems the attached JPEG is visible.

Thanks
 

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static pressure head at a point inside a body of liquid is given by ρgh , as Astronuc Stated, where h is the height of the column of water above the point of interest, think of it this way, if you have two paper cups filled to the brim with water, and you put a hole in each cup, one near the top, and one near the bottom, the water will flow out faster from the hole near the bottom , because the h is higher, ie the column of water is higher, hence the static pressure is higher. similarly, your piston with the hose near the base of the tank will experience greater pressure
 
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