Who used a trignometric formula to estimate pi to 16 decimal places?

  • Context: Undergrad 
  • Thread starter Thread starter Drez1985
  • Start date Start date
  • Tags Tags
    Manipulation
Click For Summary
SUMMARY

The discussion centers on the trigonometric formula used by Jamshid al-Kashi to estimate pi to 16 decimal places, specifically the expression C_n=√2(2r+C_(n-1)), with C_1=r√3. The simplification of √(2(2r+r√3)) to r√(2r+√3) is confirmed to hold true under specific conditions for r. The formula is referenced from Michael J. Bradley's book "The Age of Genius - 1300-1800". Participants clarify the correct notation and provide insights into the mathematical derivation.

PREREQUISITES
  • Understanding of trigonometric formulas
  • Familiarity with algebraic simplification techniques
  • Knowledge of the historical context of Jamshid al-Kashi's work
  • Basic skills in mathematical notation and expressions
NEXT STEPS
  • Study the derivation of C_n=√2(2r+C_(n-1)) in detail
  • Explore the historical significance of Jamshid al-Kashi's contributions to mathematics
  • Learn about the methods used to estimate pi in historical contexts
  • Investigate the implications of using trigonometric formulas in modern mathematics
USEFUL FOR

Mathematicians, historians of science, educators, and students interested in the historical methods of calculating pi and the contributions of early astronomers like Jamshid al-Kashi.

Drez1985
Messages
2
Reaction score
0
How does √(2(2r+r√3) simpilfy to r√(2r+√3) ?

Read about the formula in a book about Jamshid al-Kashi, the great Iranian astronomer who used the above formula to determine pi to 16 decimal places.

All help is much appreciated.
 
Mathematics news on Phys.org
Are you sure you wrote it correctly?
The only two cases when \sqrt{2(2r+r\sqrt 3)}=r\sqrt{2r+\sqrt 3}, are when r=0, or when r=\frac{\sqrt{35+16\sqrt 3}-\sqrt 3}{4}.

Did you mean \sqrt{r(2r^2+\sqrt 3 r)}=r\sqrt{2r+\sqrt 3} ?
 
Yes, I'm sure; I wrote off the formula from a book called "The Age of Genius - 1300-1800" by Michael J. Bradley.

Jamshid al-Kashi used the following trignometric formula (as a way to estimate pi):

C_n=√2(2r+C_(n-1))

where C_1=r√3

By first substituting C_1 into the expression for C_2, supposedly, you will end up with:

C_2 = r√(2r+√3)

Was it any help?

P.s. Sorry for the messy notation, but when pasting from the excel equation writer onto this webpage, strange things happens...
 

Similar threads

Replies
5
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 62 ·
3
Replies
62
Views
11K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 11 ·
Replies
11
Views
12K