Why a lamp with X PD passes Y current

In summary, the string of electric lamps for decorating a Christmas tree consists of 20 12 V lamps connected in series across the 240 V mains with a power consumption of 24 W. The resistance of each lamp is 120 Ω, and if one lamp becomes short-circuited, the new power consumption of the string is approximately 25.3 W. When one of these lamps is tested by applying a potential difference of 0.1 V, it passes a current of 10 mA due to the decrease in power consumption. The cause of this change in resistance is the conversion of electric energy into light energy by the metal spring (filament) inside the glass of the lamp.
  • #1
moenste
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12

Homework Statement


A string of electric lamps for decorating a Christmas tree consists of 20 12 V lamps connected in series across the 240 V mains. The power consumption of the whole string is 24 W.

(a) What is the resistance of each lamp?
(b) If one lamp becomes short-circuited, what is approximately the new power consumption of the string?
(c) Explain why, when one of these lamps is tested by applying a potential difference of 0.1 V, it passes a current of 10 mA.

Answers: (a) 120 Ω, (b) 25.3 W.

2. The attempt at a solution
(a) First find the power consuption of 1 lamp: 24 W / 20 = 1.2 W per 1 lamp. Then we find the resistance: P = V2 / R → R = V2 / P = 122 / 1.2 = 120 Ω (resistance of each lamp).

(b) In that case we'll have the same voltage consumption (20 lamps on 12 V = 240 V), but we'll get only 19 lamps with resistance of 120 Ω (2280 Ω). So the new power consumption of the string is: P = V2 / R = 2402 / 2280 = 25.3 W.

(c) This part I don't understand completely. The resistance should be R = V / I = 0.1 / 0.01 = 10 Ω. But what should I compare with what?
 
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  • #2
moenste said:
(c) This part I don't understand completely. The resistance should be R = V / I = 0.1 / 0.01 = 10 Ω. But what should I compare with what?
What might make a resistance change value depending up on operating conditions?

You recently worked on an exercise where a resistor in a circuit changed over time after power was applied. What was thought to be the cause of that change in resistance?
 
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  • #3
gneill said:
What might make a resistance change value depending up operating conditions?

You recently worked on an exercise where a resistor in a circuit changed over time after power was applied. What was thought to be the cause of that change in resistance?
You mean "ON operating conditions"?

Well, we had a resistance of 120 Ohm and now we have a resistance of 10 Ohm. As we can see the PD was changed -- V = 0.1 V, though we don't know the original current. So the answer is "it passes a current of 10 mA because the PD has changed from 12 V to 0.1 V"?

I just don't understand what the answer supposed to be. "Because X has changed (resistance / voltage / current) and therefore the lamp passes a current of 10 mA"?
 
  • #4
moenste said:
You mean "ON operating conditions"?
Yes. Or perhaps "upon" :smile:. Thanks for catching that.
Well, we had a resistance of 120 Ohm and now we have a resistance of 10 Ohm. As we can see the PD was changed -- V = 0.1 V, though we don't know the original current. So the answer is "it passes a current of 10 mA because the PD has changed from 12 V to 0.1 V"?

I just don't understand what the answer supposed to be. "Because X has changed (resistance / voltage / current) and therefore the lamp passes a current of 10 mA"?
The PD is something external to the lamp that is applied for texting purposes. What you need to think about is what might be different about the lamp itself under those conditions. What's the difference between a lamp that's running with its normal operating PD of 12 V and one operating with just 0.1 V? Do you expect the lamp to be the same brightness in both cases? What makes a lamp glow?
 
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  • #5
gneill said:
Yes. Or perhaps "upon" :smile:. Thanks for catching that.

The PD is something external to the lamp that is applied for texting purposes. What you need to think about is what might be different about the lamp itself under those conditions. What's the difference between a lamp that's running with its normal operating PD of 12 V and one operating with just 0.1 V? Do you expect the lamp to be the same brightness in both cases? What makes a lamp glow?
A lamp consumes 12 V, however, when only 0.1 V are applied to the lamp it is clearl that the lamp will pass less current and be less bright than under normal conditions.
 
  • #6
moenste said:
A lamp consumes 12 V, however, when only 0.1 V are applied to the lamp it is clearl that the lamp will pass less current and be less bright than under normal conditions.
Again, what makes a lamp glow?
 
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  • #7
gneill said:
Again, what makes a lamp glow?
When we put the cable into the wall. It gives it energy, current?
 
  • #8
moenste said:
When we put the cable into the wall. It gives it energy, current?
What , physically, makes a lamp filament glow? What's the difference between a filament that's switched off and one that's giving off light?
 
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  • #9
gneill said:
What , physically, makes a lamp filament glow? What's the difference between a filament that's switched off and one that's giving off light?
A bulb makes a lamp glow?
 
  • #10
moenste said:
A bulb makes a lamp glow?
No, the bulb is just a container for the filament.

Please do a web search on "How do light bulbs work?". This is an important concept for this question (and the one you answered previously about why the potential across a resistor changed over time!).
 
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  • #11
gneill said:
No, the bulb is just a container for the filament.

Please do a web search on "How do light bulbs work?". This is an important concept for this question (and the one you answered previously about why the potential across a resistor changed over time!).
Electric energy is converted in light energy? The metal spring (filament) inside the glass shines.

moenste said:
(c) Explain why, when one of these lamps is tested by applying a potential difference of 0.1 V, it passes a current of 10 mA.
Isn't it just "if 0.1 V is applied the lamp will pass a current of 10 mA". Since the current is based on PD.
 
  • #12
moenste said:
Electric energy is converted in light energy? The metal spring (filament) inside the glass shines.
How is electric energy converted to light energy? Why does the filament shine? What makes the filament different when it's passing a current from when it's not? What physical property of the material is different?
(Hint: Why isn't it a good idea to touch a 100 W lightbulb while it's shining?) :wink:

Isn't it just "if 0.1 V is applied the lamp will pass a current of 10 mA". Since the current is based on PD.
If that were true the current would be 0.1V / 120 Ω = 0.833 mA. Not the 10 mA that is claimed. What is different about the filament between these two cases?
 
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  • #13
gneill said:
How is electric energy converted to light energy? Why does the filament shine? What makes the filament different when it's passing a current from when it's not? What physical property of the material is different?
Current goes through the whole circuit.

gneill said:
If that were true the current would be 0.1V / 120 Ω = 0.833 mA. Not the 10 mA that is claimed. What is different about the filament between these two cases?
Hm, indeed it is 0.833 mA. In that case no idea what is different. It is only said that why if V = 0.1 V applied the current is 10 mA. Maybe it is short-circuited and because the current doesn't reach the lamp and uses the shortcut, the current speed increases and the cable heats up (I read about it in the short-circuit material).
 
  • #14
moenste said:
Current goes through the whole circuit.Hm, indeed it is 0.833 mA. In that case no idea what is different. It is only said that why if V = 0.1 V applied the current is 10 mA. Maybe it is short-circuited and because the current doesn't reach the lamp and uses the shortcut, the current speed increases and the cable heats up (I read about it in the short-circuit material).
Current goes through all the wiring in the circuit. Why doesn't the whole circuit glow? What's different about the filament?

Why/when do the elements on an electric stove glow? How about in an electric toaster? Or a space heater?
 
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  • #15
gneill said:
Current goes through all the wiring in the circuit. Why doesn't the whole circuit glow? What's different about the filament?

Why/when do the elements on an electric stove glow? How about in an electric toaster? Or a space heater?
It is made out of a different material.

No idea actually. This is a far as I could go:
moenste said:
Maybe it is short-circuited and because the current doesn't reach the lamp and uses the shortcut, the current speed increases and the cable heats up (I read about it in the short-circuit material).
I think this is logical.
 
  • #16
moenste, did you look up how a lightbulb works? What makes it shine?
 
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  • #17
gneill said:
moenste, did you look up how a lightbulb works? What makes it shine?
Yes I looked it up. Current flows through the components and filiament lights when temperature increases.
 
  • #18
moenste said:
Yes I looked it up. Current flows through the components and filiament lights when temperature increases.
[Emphasis in the quote is mine] The temperature increases. Very hot things give off visible light. Like fire, molten metal, the Sun, and so on.

The filament gets hot because it has resistance and current flowing through a resistance causes power to be dissipated in the form of heat. When the temperature gets high enough it glows.

Another property of metals such as filaments are made of is that as they get hot their electrical resistance goes up. The hotter they get the higher the resistance. So what might you say abut the resistance of a cold filament versus that of a hot filament?
 
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  • #19
gneill said:
Another property of metals such as filaments are made of is that as they get hot their electrical resistance goes up. The hotter they get the higher the resistance. So what might you say abut the resistance of a cold filament versus that of a hot filament?
A hot filament has more resistance and a cold filament has less resistance?
 
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  • #20
moenste said:
A hot filament has more resistance and a cold filament has less resistance?
Right :approve:

So can you see how to apply this to part (c)?
 
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  • #21
gneill said:
Right :approve:

So can you see how to apply this to part (c)?
moenste said:
(c) Explain why, when one of these lamps is tested by applying a potential difference of 0.1 V, it passes a current of 10 mA.
It has less resistance and it is cold? Dosn't sound like a decent answer to me... The question is about "why it passes a current of 10 mA". Because it has a cold filament and has less resistance?
 
  • #22
moenste said:
It has less resistance and it is cold? Dosn't sound like a decent answer to me... The question is about "why it passes a current of 10 mA". Because it has a cold filament and has less resistance?
That is the answer. Regardless of how it sounds, that's the physics involved. The cold filament has only 10 Ω versus 120 Ω when it's operating at full power.
 
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  • #23
Hi.Could you please tell me which book is this question from?
 
  • #24
isa_abj said:
Hi.Could you please tell me which book is this question from?
This thread over 4 years old. The Original Poster is no longer registered as a Physics Forums user.
 

1. Why does a lamp with lower PD pass a higher current?

According to Ohm's Law, the current passing through a circuit is directly proportional to the voltage or potential difference (PD) across it. This means that when the PD decreases, the current will increase to maintain the same resistance.

2. How does the PD affect the resistance of a lamp?

The PD across a lamp directly affects its resistance. As the PD increases, the resistance of the lamp will also increase. This is because the electrons in the circuit will experience more opposition to their flow, resulting in a decrease in current.

3. Can the PD and current passing through a lamp be directly proportional?

Yes, the PD and current in a lamp can be directly proportional if the lamp has a constant resistance. This means that if the PD doubles, the current will also double, and if the PD is halved, the current will also be halved.

4. What happens to the current if the PD is too high?

If the PD is too high, it can cause the lamp to burn out or short circuit. This is because a high PD will result in a high current, which can generate excess heat and damage the lamp's components.

5. How does the material of the lamp affect the relationship between PD and current?

The material of the lamp can affect the relationship between PD and current as different materials have different resistances. For example, a lamp made of tungsten will have a higher resistance than a lamp made of copper, resulting in a different relationship between PD and current.

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