Why Am I Getting an Extra Area in My Karnaugh Map Simplification?

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The discussion revolves around a user struggling with Karnaugh map simplification, specifically encountering an extra area in their solution. They are working with the function ∫ = Ʃ(0,5,6,7,13) and consistently arrive at a solution that includes overlapping areas in the Karnaugh map. Another user suggests that the simplified equation can be refined using the Consensus Theorem, leading to a more accurate representation without overlaps. Additionally, the original poster seeks recommendations for free or open-source software to visually model the function. The conversation highlights the importance of understanding simplification rules in digital logic design.
Koopan
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Hi,
I'm new to this forum.
My problem led me here.

Homework Statement


I need to solve this, using simplifying rules.
∫ = Ʃ(0,5,6,7,13)

But I always get one extra area when checking with Karnaugh map, which isn't necessary.

Homework Equations


∫() = a' b' c' d' + a' b c' d + a' b c d' + a' b c d + a b c' d


The Attempt at a Solution


Well I get always this as a solution, no matter the order i simplify

∫() = a' b' c' d' + b c' d + a' b c + a' b d


Now when applied to Karnaugh map the areas (equation parts from left to right 1-4) 1, 2, 3 are the solution I get when only using the map. But 4 overlaps with 2 and 3.

http://s8.postimage.org/dbo6zqrab/img.jpg
img.jpg


If anyone has time to help me out, then please do.

Thanks
 
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Koopan said:
I need to solve this, using simplifying rules.
\int = \sum (0,5,6,7,13)
Can you explain what this means, and how you went about solving it? I might catch on to what you are doing.
 
The k-map produces the right result: The simplified equation is:

a' b c +b c' d + a' b' c' d'

There is more you can do with your equation

a' b' c' d' + b c' d + a' b c + a' b d

Hint: Consensus Theorem :)
 
Thank you Ivan92 your advice helped me solve this.

Now as I'm here does anyone know any free or opensource software for modelling this function visually?
 
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