Why Are Moments Calculated Differently for Force Components in Statics?

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The discussion addresses the calculation of moments for a 50 N force applied to a pulley at a 45-degree angle. The confusion arises from why the moment calculated as -50(0.15) does not equal the sum of the moments from its components, which is (-50cos45)(0.15) + (-50sin45)(0.15). It is clarified that the force is not applied at the top of the pulley, and the perpendicular distance used in the component calculations is not 0.15 m. To obtain consistent results, one should either calculate the correct perpendicular distance or apply the cross product rule. Understanding these principles ensures accurate moment calculations in statics.
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Here is my question:
http://imageshack.us/photo/my-images/31/unledasm.png/
On this figure, there is a 50 N force on the bigger pulley. When summing up the moments about the x-axis, why isn't -50(0.15) [circled on figure] the same as (-50cos45)(0.15) + (-50sin45)(0.15), which is the sum of the moments of its components?
 
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eurekameh said:
Here is my question:
http://imageshack.us/photo/my-images/31/unledasm.png/
On this figure, there is a 50 N force on the bigger pulley. When summing up the moments about the x-axis, why isn't -50(0.15) [circled on figure] the same as (-50cos45)(0.15) + (-50sin45)(0.15), which is the sum of the moments of its components?

I have a 22" monitor, but that image is still too small to read anything?
 
eurekameh said:
Here is my question:
http://imageshack.us/photo/my-images/31/unledasm.png/
On this figure, there is a 50 N force on the bigger pulley. When summing up the moments about the x-axis, why isn't -50(0.15) [circled on figure] the same as (-50cos45)(0.15) + (-50sin45)(0.15), which is the sum of the moments of its components?
I was able to see the image. The 50 N force is applied to the pulley tangent to its circumference at a point 45 degrees counterclockwise from its vertical z axis. It is not applied at the top of the pulley. When you break it into its components, the perpendicular distance is not 0.15 m. Either calculate the perpendicular distance, or use the cross product rule, when calculating the sum of moments this way, and you get the same result.
 
PhanthomJay said:
I was able to see the image. The 50 N force is applied to the pulley tangent to its circumference at a point 45 degrees counterclockwise from its vertical z axis. It is not applied at the top of the pulley. When you break it into its components, the perpendicular distance is not 0.15 m. Either calculate the perpendicular distance, or use the cross product rule, when calculating the sum of moments this way, and you get the same result.

This helped me. Thanks.
 
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