Why Aren't My Calculated Currents Correct in This Circuit Analysis?

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The discussion centers on a circuit analysis problem where the user struggles to calculate currents using an alternative method instead of Kirchhoff's laws. The user incorrectly assumes the resultant EMF of two opposing batteries and neglects one, leading to incorrect resistance calculations. Responses emphasize that the batteries are not in series due to a middle branch, which affects current flow. The consensus is that Kirchhoff's laws must be applied to accurately determine the currents. Ultimately, the user is advised to adhere to these laws for a correct solution.
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Homework Statement


In the given circuit find the current i1,i2,i3.
(Image of the circuit is attached)

Homework Equations


current=(emf)/total resistance

The Attempt at a Solution


The original question actually asks me to find the currents using Kirchoff's laws .Since I feel this method to be a little tedious I tried to do it another way.
But the problem is the answers are not coming correct this way ,(which is as follows )

First since the two cells are connected opposite to each other i have assumed the resultant emf of the 21V to be 4V and I have neglected the other 17V cell.
then considering 2Ω and 5Ω resistances to be parallel to each other their resultant comes to be
(10/7)Ω .And this one being in series with 3Ω, The final resistance of the circuit comes out to be
(31/7)Ω.
Accordingly current should be i1=28/31 A
I am going seriously wrong somewhere , but can't figure out where.:cry: .
Can you please help?
Thanks in advance!
 

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1/2" said:

The Attempt at a Solution


The original question actually asks me to find the currents using Kirchoff's laws .Since I feel this method to be a little tedious I tried to do it another way.
But the problem is the answers are not coming correct this way ,(which is as follows )

First since the two cells are connected opposite to each other i have assumed the resultant emf of the 21V to be 4V and I have neglected the other 17V cell.

What you have presumed would have been correct if the two batteries would have been in series .Do you think the batteries are in series ?

Please be careful ,there is a middle branch between the two batteries.The current flowing through them will not be the same .

1/2" said:
then considering 2Ω and 5Ω resistances to be parallel to each other their resultant comes to be
(10/7)Ω .

Wrong .

1/2" said:
And this one being in series with 3Ω

Wrong .
 
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1/2" said:
The original question actually asks me to find the currents using Kirchoff's laws .Since I feel this method to be a little tedious I tried to do it another way.
But the problem is the answers are not coming correct this way ,(which is as follows )
.
.
.
I am going seriously wrong somewhere , but can't figure out where.:cry: .
Can you please help?
Thanks in advance!
You'll need to use Kirchhoff's rules here, tedious as they are.

As Tanya Sharma said, since the two batteries are not actually in series, you can't simply subtract their voltages.
 
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