Why Can Tangential Acceleration Vector's Scalar Component Not Be Negative?

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Homework Help Overview

The discussion revolves around the properties of tangential acceleration in circular motion, specifically questioning why its scalar component cannot be negative. Participants explore the relationship between tangential acceleration and velocity, as well as the definitions of unit vectors in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants examine the definitions of tangential and radial acceleration, questioning the conditions under which tangential acceleration can be considered positive or negative. There is a focus on the relationship between the direction of the tangential unit vector and the velocity vector.

Discussion Status

Some participants have provided insights into the definitions of unit vectors and their relationship to acceleration and velocity. There is an ongoing exploration of the implications of these definitions, with no explicit consensus reached on the original poster's question.

Contextual Notes

Participants are discussing the implications of scalar components in the context of circular motion and the definitions of acceleration, with some confusion regarding the signs associated with these components. The conversation reflects a mix of interpretations regarding the behavior of tangential acceleration.

mike 2012
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we already know that the scalar component of the Centripetal ( Radial ) Acceleration vector is always negative because it's ALWAYS directed to the opposite direction of its unit vector ( toward the center of the circle ) , and this is satisfying to me and to the formula .

however , when it comes to the scalar component of the Tangential Acceleration vector , I get confused because its formula always gives positive outputs . which means it's always directed to the same direction of its unit vector .

the question is : why can the scalar component of the Tangential Acceleration vector not be negative and directed to the opposite direction of its unit vector ?

if it can be negative and directed to the opposite direction of its unit vector , why does not the formula satisfy negative outputs ?

http://imageshack.us/scaled/landing/26/hhhhjz.png
 
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Hi Mike, welcome to PF. :smile:

The tangential unit vector points always in the same direction as the velocity: it is defined as the velocity vector divided by the magnitude of velocity. If the speed increases, the tangential acceleration is positive. In case of decreasing speed, the tangential acceleration is negative.
In the equation you quoted |v| is the speed, and d|v|/dt can be both positive and negative.

ehild
 


ehild said:
The tangential unit vector points always in the same direction as the velocity


is this correct only for " the tangential unit vector " ?
because according to what I learned , any vector can be in the opposite direction of its unit vector and specified by a negative sign.

however , in case of " the tangential unit vector " , as I understood from you ; the unit vector follows the direction of the vector ( wether it's acceleration or velocity as you mentioned ) which means whatever the tangential vector is , it's positive (since its unit vector follows its direction )

and thank you for responding :)
 
Last edited:


The direction of tangential unit vector is the same as that of the velocity. So the velocity is always positive in the coordinate system defined by radial and tangential unit vectors, moving together with the body. The body can accelerate along the tangent in the direction of the velocity, then the magnitude of the velocity will increase; or it can accelerate in the opposite direction (the acceleration is negative, the body decelerates), the magnitude of velocity will decrease.
Imagine a car traveling along a circular rod. It starts from rest and accelerates - its velocity and tangential acceleration are of the same direction, the tangential acceleration is positive with respect to the direction of travel. Suddenly a deer jumps out on the road, so the driver has to brake. Now the acceleration is opposite to the direction of travel, it is negative, as the car has to slow down.

ehild
 

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