Why can we assume the temperature of a fluid is T_sat?

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Discussion Overview

The discussion revolves around the assumptions made regarding the temperature of R134a in a rigid container at a specified pressure. Participants explore whether the fluid can be considered at saturation temperature (T_sat) or if it could be in a state of compressed liquid or superheated vapor. The context includes theoretical reasoning and application of thermodynamic tables.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the assumption that the temperature is T_sat, asking how to determine if the fluid is a compressed liquid or a superheated vapor.
  • Another participant suggests checking the specific volume against the saturated tables to identify the state of the fluid at 100 kPa, noting that the specific volume lies between those of saturated liquid and saturated vapor.
  • A later reply raises a question about the implications of obtaining a quality greater than one when using the equation v=v_f + x(v_fg), inquiring if this indicates the substance is a vapor.
  • Responses indicate that the specific volume can provide insights into the state of the fluid, and that superheated tables may also be relevant for understanding the conditions of the substance.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the state of the fluid, with some suggesting it could be at saturation while others highlight the need for further analysis using specific volume data. The discussion does not reach a consensus on the assumptions made about the temperature and state of the fluid.

Contextual Notes

Participants rely on specific volume values from thermodynamic tables, which may depend on the definitions and conditions applied. The discussion highlights the importance of these values in determining the state of the fluid, but does not resolve the implications of quality exceeding one.

zachdr1
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For example, in this question..

A 11 L rigid container contains 10-kg of R134a at 100kPa. Determine the temperature and total enthalpy in the container.

Why can we just assume that the temperature we're looking for is T_sat, how do we know this isn't a compressed liquid? How do we know it isn't a superheated vapor?

The answer (-26.37) is found by looking it up in the saturated R134a table.
 
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The specific volume of your sample is 1.1 L/kg = 0.0011 m^3/kg. Look in your tables and see if you find any compressed liquid or superheated vapor with this specific volume at 100 kPa. But it does lie between the specific volume of saturated liquid and the specific volume of saturated vapor at 100 kPa.
 
Chestermiller said:
The specific volume of your sample is 1.1 L/kg = 0.0011 m^3/kg. Look in your tables and see if you find any compressed liquid or superheated vapor with this specific volume at 100 kPa. But it does lie between the specific volume of saturated liquid and the specific volume of saturated vapor at 100 kPa.
Ohhh okay that makes sense. Thank you.

This doesn't relate the the original problem I posted, but what happens if when using the equation v=v_f + x(v_fg) with the values from the saturated tables, I get a quality that is greater than one? Does that mean that the substance is actually a vapor or what?
 
zachdr1 said:
Ohhh okay that makes sense. Thank you.

This doesn't relate the the original problem I posted, but what happens if when using the equation v=v_f + x(v_fg) with the values from the saturated tables, I get a quality that is greater than one? Does that mean that the substance is actually a vapor or what?
Sure. In fact you should be able to see that from the superheated tables.
 

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