Why Did I Calculate the Cliff's Height Incorrectly?

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The diver's horizontal speed is 1.2 m/s, and he dives for 3 seconds, leading to a horizontal distance of 3.6 meters from the cliff base. The correct formula for vertical distance is y = -1/2gt², which calculates the cliff's height as 44.1 meters. The initial calculations were reversed, mistakenly stating the cliff height as 3.6 meters and the distance from the base as 44.1 meters. The diver's actual trajectory confirms the cliff is significantly taller than the horizontal distance traveled. Accurate application of the formulas reveals the cliff's height is 44.1 meters, while the diver lands 3.6 meters away.
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need help please! what am i doing wrong??

A diver running 1.2 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3.0 s later. How high was the cliff and how far from its base did the diver hit the water?

so does v = 1.2 m/s and t=3 seconds
i used the formula Vxo=X/t so i did 1.2=x/3 so x = 3.6m for the first part of the question. for the second part of the question i used the formula y=-1/2gt^2 so i did y=(-1/2)(-9.8)(3^2) = 44.1m.
so i said that the cliff was 3.6m high and the base was 44.1m away. but i got it wrong. am i using the right formulas?
 
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You got the right formulas but you switched em, he landed 3.6 m away and the cliff was 44.1m high!
 
ohh! thank you so much! it didn't sound right that a cliff was 3.6m high and he hit the water at 44.1m! lol
 
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