devious_
- 312
- 3
I need help understanding electric fields. I basically suck at answering questions related to them (I get 95% of them wrong
).
What I do know about them is:
The electric field vector moves from a positive charge (+q) to a negative charge (-q). (Is this the same case in a capacitor? I saw the vector pointing for -q to q through the dielectric of two plates.)
I also know a few equations:
E=\frac{F}{q}=k\frac{Q}{r²}
\Delta U_{e} = -\Delta W_e = - Fd = -Eqr
W = kqQ (\frac{r_{a}-r_{b}}{r_{a}r_{b}})
\Delta U_{e} = k\frac{qQ}{r}
\Delta V = \Delta \frac{U_{e}}{q} = k\frac{Q}{r}
\Delta V = \frac{\Delta W_{e}}{q} = \frac{Fd}{q} = \frac{Eq}{q}d = Ed
\Delta V = \frac{q}{C}
C = \frac{\epsilon_{0}A}{d}
I appologize if this is the wrong forum.

What I do know about them is:
The electric field vector moves from a positive charge (+q) to a negative charge (-q). (Is this the same case in a capacitor? I saw the vector pointing for -q to q through the dielectric of two plates.)
I also know a few equations:
E=\frac{F}{q}=k\frac{Q}{r²}
\Delta U_{e} = -\Delta W_e = - Fd = -Eqr
W = kqQ (\frac{r_{a}-r_{b}}{r_{a}r_{b}})
\Delta U_{e} = k\frac{qQ}{r}
\Delta V = \Delta \frac{U_{e}}{q} = k\frac{Q}{r}
\Delta V = \frac{\Delta W_{e}}{q} = \frac{Fd}{q} = \frac{Eq}{q}d = Ed
\Delta V = \frac{q}{C}
C = \frac{\epsilon_{0}A}{d}
I appologize if this is the wrong forum.