Why Do Observers A and B Perceive Light Arrival at Different Times?

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Observers A and B perceive light arrival at different times due to the timing of the explosion, which occurred 2 microseconds into the time frame. For observer A, the total time is 4 microseconds, while for observer B, it is 3 microseconds. The confusion arises from the assumption that they should see the light immediately when it reaches them, but the problem requires understanding the timing of the explosion. The additional time accounts for when the explosion happened, not just the travel time of light. This highlights the importance of considering the event's timing in relation to the observers' positions.
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here this time for the experimenter A t=4 micro sec and for B t=3 micro sec.

shouldn't they see the light at when light reaches there as in At=2 micro sec and Bt= 1micro sec.

i do not get this example could someone explain this to me.

thanks in advance
Seto
 
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If you read carefully after the Solve portion, it says the explosion occurred at 2 microseconds into the 'time frame', which simply adds 2 microsec. to what you are stating, so 4 and 3 respectively for observers A and B. It does only take 2 microsecs and 1 microsec to reach A and B, but the problem is essentially trying to get you to find when the explosion occurred.
 
i mean in stead of At=4 and Bt=3 shouldn't it me like At=2 and Bt=1?

when light reaches there they should be able to see it..so where does the extra 2 for At and extra 2 for Bt come from
 
oh its the time at which explosion took place
 
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