Why do r and F need to be perpendicular for two angles to give the same torque?

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For two angles to produce the same torque, the vectors r (radius) and F (force) must be perpendicular, as torque is defined by τ = rF sin θ. When r and F are not perpendicular, two angles can yield the same torque due to the sine function's properties, specifically sin θ = sin(π - θ). As the angle approaches perpendicularity, torque increases, but the relationship between the angles remains valid. The discussion highlights the importance of understanding torque's dependence on the angle between the force and radius vectors. This clarification emphasizes that the magnitude of torque can be the same for two different angles when r and F are not perpendicular.
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Unless r and F are perpendicular, there are always two angles between their directions that give the same torque for given magnitudes of r and F. Explain why?

Perhaps I cannot visualize the question, but I cannot see how this can be. As the force moves to the perpendicular position the torque increases. Am I missing something?
 
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Use the definition of torque. If one angle between the p.v and force vector is theta, what about the other?

Edit: I guess this holds only for the magnitude of the torque.
 
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\tau = rF \sin \theta

sin \theta = \sin (\pi - \theta)​

:smile:
 
I guess I figured that would put the angle outside of between the two angles.
 
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