Why do signals shift in opposite directions when time shifted in opposite ways?

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Time shifting signals in opposite directions reveals that x(-t) reflects the function around the y-axis, leading to different behaviors when time-shifting. When x(-t) is shifted to x(-t-2), it moves toward the negative t-axis, while x(t) shifted to x(t-2) moves toward the positive t-axis. This discrepancy arises because x(-t) represents a time-reversed function, meaning that the delay behaves oppositely compared to standard time shifts. Visualizing these functions with simple signals, like pulses or step functions, clarifies the reflection effect. Understanding these shifts requires recognizing the fundamental differences in how time reversal interacts with time delays.
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when we have x(-t) and we time shift it say x(-t-2) it shifts toward the -ve t axis.. where as x(t-2) the function is shifted on the + axis..why is it so??

see when we say there are 2 functions x(t) and x(t-2) it means x(t-2) is delayed by 2 sec with respect to x(t) therefore it shifts in the positive x direction.. does'n't the same apply for x(-t) and x(-t-2) the second function is time delayed by 2 secs wid respect to the first so even it should shift to the positive x axis..isn't it?
 
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x(-t-2) has been time reversed so the opposite applies. It is best to think of these by drawing out simple arbitrary signal (like a pulse or step function) and remember that x(-t) is just reflecting it around the y-axis (think of the function as a rigid frame that can be rotated at the y-axis).
 
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