Why Do Three Blocks on a Frictionless Surface Accelerate at the Same Rate?

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In a frictionless scenario with three blocks of varying masses, a horizontal force of 2.4 N is applied to the first block, A. The key point of discussion is that all three blocks will accelerate at the same rate due to the absence of friction, which prevents any relative motion between them. Since blocks B and C are in contact with block A, they cannot accelerate slower or faster than A without violating Newton's laws of motion. This understanding clarifies why the assumption of equal acceleration is valid. The conclusion emphasizes that the lack of friction is crucial for this uniform acceleration among the blocks.
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Homework Statement



On a surface without friction, we have 3 blocs with mass A=0,4 kg B=0,1 Kg C=0,3 Kg which are placed one beside the other, with A being first, B second and C third.. If we push on the bloc A with a horizontal force of 2,4 N, determine what is the acceleration and what are the forces of the normals which are located between the blocs.

http://imgur.com/F9PQwKK

Homework Equations



Sum force of x = m * a(x)

The Attempt at a Solution


I was able to resolve the problem and got the right answers. What I was wondering is why should I assume that the acceleration is going to be the same for the 3 blocs ? I was able to solve the problem because I assumed this to be true, but I don't know why it is. I guess that the fact there's no friction makes this true. any help ?
 
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Well, given the picture, B and C can't accelerate slower than A. There also is nothing that could make them accelerate faster.

Does that answer your question ?
 
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BvU said:
Well, given the picture, B and C can't accelerate slower than A. There also is nothing that could make them accelerate faster.

Does that answer your question ?
Said this way, it makes sense. Ty
 
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