Why Do Time Intervals Differ in Motion Analysis Problems?

AI Thread Summary
The discussion revolves around understanding the time intervals used in a motion analysis problem involving a man's movement. The confusion stems from the specific time intervals mentioned for calculating average velocity and acceleration, particularly why the intervals are set from 2.00 min to 8.00 min instead of the entire duration of the man's movement. Participants clarify that the intervals are arbitrary values chosen by the problem setter, which are essential for solving the problem. The original poster eventually realizes their misunderstanding regarding the problem statement. The conversation highlights the importance of carefully reading and interpreting the details in physics problems.
cattalion
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Homework Statement


From t=0 to t=5.00 min, a man stands still, and from
t=5.00 min to t=10.0 min, he walks briskly in a straight line at a
constant speed of 2.20 m/s. What are (a) his average velocity vavg (v average)
and (b) his average acceleration aavg in the time interval 2.00 min to
8.00 min? What are (c) vavg and (d) aavg in the time interval 3.00 min
to 9.00 min?

I know the solution, but my question is: why is the entire time interval for part a is equal to delta t= 8–2= 6 min? Where did the 8 and 2 come from? Part b and c, I also am confused by the time intervals. I have the solution attached and confusions marked in red. Can anyone clarify this?

Homework Equations


Average velocity: Delta x/delta t

Average acceleration: Delta v/delta t

The Attempt at a Solution


(The solution is attached).
 

Attachments

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cattalion said:
Where did the 8 and 2 come from?
The time intervals are all arbitrary values selected by the problem setter. They have no special significance.
 
haruspex said:
The time intervals are all arbitrary values selected by the problem setter. They have no special significance.

I still don't understand :frown: They do matter because I would need to use those values to find the average velocity. Wouldn't I subtract 10 - 5 minutes instead of 8 - 2 minutes since it says: "From t=0 to t=5.00 min... and from t=5.00 min to t=10.0 min..."?
 
cattalion said:
They do matter because I would need to use those values to find the average velocity. Wouldn't I subtract 10 - 5 minutes instead of 8 - 2 minutes since it says: "From t=0 to t=5.00 min... and from t=5.00 min to t=10.0 min..."?
Yes, of course they matter. Those are the values you are told to use:
(b) his average acceleration aavg in the time interval 2.00 min to 8.00 min
But you asked where they came from. The answer is that they came out of the problem setter's head.
 
check with Bashar
 
There something must be wrong with my eyes, because I "misread" the problem. It's sad though because I was trying to figure out where the times came from for a couple of days, and I finally saw "his average acceleration aavg in the time interval 2.00 min to 8.00 min?" It like miraculously appeared to me.

Thank you for all those that helped. Seriously think something wrong with my eyes.
 
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