Why Do We Use Sine for the X-Component in Physics Problems?

AI Thread Summary
The discussion clarifies why the sine function is used for the x-component of forces in physics problems involving inclined planes. In the case of a skier on a slope, the gravitational force acting down the slope is represented as mg sin(theta), where theta is the angle of the slope. This is derived from the geometry of the situation, specifically the relationship between the forces and the angle of inclination. The normal force and gravitational force create a right triangle, making sine the appropriate function for calculating the x-component. Understanding this relationship is crucial for solving problems involving forces on slopes.
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Homework Statement



I am worried that I don't understand a basic part of figuring out the component forces in the following problem. I have a full worked example but there is a few steps which I don't understand why we use sin for the x component and not cos (understand why I am really worried as it appears to be basic trig :/)

A 58-kg skier is coasting down a 25° slope, as Figure 6.7a shows. Near the top of the slope, her speed is 3.6 m/s. She accelerates down the slope because of the gravitational force, even though a kinetic frictional force of magnitude 71 N opposes her motion. Ignoring air resistance, determine the speed at a point that is displaced 57 m downhill.


Homework Equations


vf = √2(KEf) / m
= √(2(1/2 mv02 + Sigma F cos theta s)/m
= √(2(1/2 mv02 + mg sin 25 - fk s) /m
= √(2(1/2 mv02 + 170N cos 0 x 57) / 58
= 19m/s

The Attempt at a Solution



This was in my textbook:

a free-body diagram for the skier and shows the three external forces acting on her: the gravitational force , the kinetic frictional force , and the normal force . The net external force along the y-axis is zero, because there is no acceleration in that direction (the normal force balances the component mg cos 25° of the weight perpendicular to the slope). Using the data from the table of knowns and unknowns, we find that the net external force along the x-axis is:

SigmaF = mg sin 25 - fk
= (58)(9.8)(sin 25)(71)
= 170N


I look at sin and think we are looking at y component. I can't see why we would used sin for x component - can someone explain?

Many thanks

H
x

ps. please forgive formating - each time I use latex it just puts large gaps in the place of symbols :)
 
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AH! My free body diagram was incorrect - all good don't need a reply. thanks anyway those who read through my problem. Sorry for inconvenience.
 
Friction is a nonconservative force, so you can't use conservation of energy.

Sin is used for the x component because you have to draw a similar triangle for the normal force of the skiier. The angle between the force opposite the normal force and gravity is theta. Then trig will tell you that the x component is mgsin(theta).
 
Mindscrape said:
Friction is a nonconservative force, so you can't use conservation of energy.

Sin is used for the x component because you have to draw a similar triangle for the normal force of the skiier. The angle between the force opposite the normal force and gravity is theta. Then trig will tell you that the x component is mgsin(theta).

Thank you very much! This really helped me consolidate my understanding :)
 
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