Why Does a Dipole Experience Zero Force from Another Dipole?

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A dipole experiences zero force from another dipole due to the equal and opposite forces acting on its charges, which cancel each other out. In the given scenario, the first dipole consists of charges Q+ and Q- along the y-axis, while the second dipole with charges q+ and q- is positioned on the x-axis. The calculations indicate that the forces on each charge of the second dipole from the first dipole result in a net force of zero. However, the torque on one dipole due to another can be calculated by considering the different distances and angles of the charges, as the forces are vector quantities. Understanding these interactions is crucial for analyzing dipole behavior in electric fields.
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I've worked this problem out, but I seem to get zero force on the second dipole due to the first dipole.

The problem is situated as such:

There are Q charges along the y axis: Q+ and Q-. They are a distance r apart. Their distance from the origin (at the center of the two charges) is r/2. This is the first dipole.

The second dipole is on the the x-axis, to the right. These have charges q+ and q-. The distance q+ has from the origin is x-d/2, for q-, the distance is x+d/2. (q+ and q- are a distance 'd' apart).


dip.jpg


I took the force on each q+ and q- charge by Q+ and Q-. I took the tangent as the distance between them, but I seem to get zero.

Also, how would torque on one dipole due to another be calculuated?
 
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The force is a vector quantity hence we have to add them vectorically and then the resultant will not be zero on each charge q. The distances of +q and -q are different so the resultant force on +q and -q will not be zero.
 
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