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The standard output waveform of a photomultiplier tube has a "negative" pulse, like below. Why is the amplitude negative?
The output waveform of a photomultiplier tube (PMT) produces a negative pulse due to the anode current being converted to voltage through a grounded resistor. The photo-cathode and multiplier dynodes are at a negative potential relative to the anode, resulting in this negative output. The conventional current flows from ground through the resistor to the anode, reinforcing the negative pulse characteristic. Understanding the historical context, PMTs were developed in the 1930s, with significant contributions from inventors like Philo Farnsworth and Iams.
PREREQUISITESElectronics engineers, physicists, and anyone involved in designing or utilizing photomultiplier tubes in various applications, including imaging and detection systems.
Best answer so far.hutchphd said:And the electrons are negative !
I think @phinds was better. It's not impossible to design a circuit where the pulse is positive, even though the electrons are negative. A PMT is but one element in a circuit.sophiecentaur said:Best answer so far
The conventional current flows from ground, down through the current to voltage resistor to the anode. That is why the pulse is negative.hutchphd said:And the electrons are negative !
But it does make a practical difference where ground potential is chosen. These were developed in the 1930's. I think I'll stick with door #1...Vanadium 50 said:A PMT is but one element in a circuit.
I have used a PMT tube with grounded cathode as part of a TV camera. But grounded cathode not useful for DC outputs referenced to ground.hutchphd said:But it does make a practical difference where ground potential is chosen. These were developed in the 1930's. I think I'll stick with door #1...