Why Does a Rolling Sphere Climb Higher Than a Sliding Particle?

AI Thread Summary
A uniform sphere and a sliding particle, both starting with the same initial speed, ascend an incline and reach different maximum heights due to their differing motion types. The sphere rolls without slipping, while the particle slides without friction. Using conservation of energy principles, it can be shown that the sphere achieves a maximum height that is 7/5 times higher than that of the particle. The moment of inertia for the uniform sphere is crucial for this calculation, and while specific masses are not provided, they will ultimately cancel out in the energy equations. Understanding the contributions of both rotational and translational kinetic energy is key to solving the problem.
connorc234
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Homework Statement


A uniform sphere and a particle are sent one-by-one with the same initial speed up the same incline. Each rises to a maximum height before falling back towards the starting point. The sphere rolls without slipping; the particle slides without friction. Use conservation of energy to show that the maximum height gained by the sphere is a factor 7/5 times that gained by the particle

Homework Equations


I = (2/5)MR^2

The Attempt at a Solution



In the first part of the question I'm asked to prove the moment of inertia for a hollow sphere and then a uniform sphere. I've done that and gotten the above equation for uniform sphere. But I don't know to apply it in this case. I'm not given any masses for either body. Any help?[/B]
 
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connorc234 said:
I'm not given any masses for either body. Any help?
So plug in a (different) unknown for each mass and see where it goes. Just maybe the masses will cancel out later.
 
Like haruspex said, the masses don't matter, they'll cancel out. Keep in mind that the total initial energy possessed by the sphere will be comprised of rotational and translational kinetic energy.
 
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