Why does AC have less copper loss than DC

AI Thread Summary
AC power transmission experiences less copper loss compared to DC primarily due to its ability to operate at higher voltages, which results in lower current for the same power output. This reduced current leads to diminished I^2R losses in the copper wires. Additionally, the availability of transformers allows for efficient high-voltage transmission and subsequent step-down to usable voltages, a process not as effective for DC. The skin effect in AC does increase resistance at higher frequencies, but the overall benefits of reduced current and efficient voltage transformation outweigh this drawback. Consequently, AC remains the preferred choice for power distribution systems.
Buggsy GC
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Hi there everyone, I'm doing some study on electronics and the section on the advantages of A/C over DC mentioned that AC has less copper loss (I^2 x R), But to me this seems contradictory to the skin effect. Could someone please tell me why AC has less copper loss.
 
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For the same voltage and for the same power transmitted over a copper line, DC has less power loss. https://en.wikipedia.org/wiki/High-voltage_direct_current

However the reason that AC power transmission has dominated is that the equipment to transform between high voltage (in order to transmit the power for fewer losses) and low voltage (power for domestic use) is cheaper and less complicated. AC generators were also cheaper and more efficient.
 
Buggsy GC said:
Hi there everyone, I'm doing some study on electronics and the section on the advantages of A/C over DC mentioned that AC has less copper loss (I^2 x R), But to me this seems contradictory to the skin effect. Could someone please tell me why AC has less copper loss.

I suspect this is confused. Most likely it's due to the answer that Delta gave eg...

AC power transmission is done at higher voltage. Higher voltage implies lower current for same power. Lower current means lower I2R losses in the copper wire.
 
Buggsy GC said:
Hi there everyone, I'm doing some study on electronics and the section on the advantages of A/C over DC mentioned that AC has less copper loss (I^2 x R), But to me this seems contradictory to the skin effect. Could someone please tell me why AC has less copper loss.
This is probably in reference to the development of the area-wide power distribution system, in an era when the choice was basically between DC all-the-way or AC all-the-way. Transformers enabled the efficient transmission of AC at high tension followed by a step-down to consumer voltages, whereas there was no equivalent available for efficiently stepping down DC at the power levels involved.

Transmitting low tension DC throughout a power network involves cripplingly-high I2⋅R losses.
 
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