Why Does Bernoulli's Equation Seem Incorrect for a Rotating Fluid in a Bucket?

  • Thread starter Thread starter jbar18
  • Start date Start date
  • Tags Tags
    Fluid Rotating
jbar18
Messages
53
Reaction score
0

Homework Statement



What is wrong with the following argument from Bernoulli's equation?

Suppose a fluid in a bucket is rotating under gravity with constant angular velocity W so that velocity is:

u = (-\Omega y,\Omega x, 0).

Then:

\frac{P}{\rho} + \frac{u^2}{2} + gz = constant,

z = constant - \frac{(\Omega)^2}{2g} (x^2+y^2)

But this implies that the highest point of the water is in the middle, which is obviously not true.

2. The attempt at a solution

I was wondering if perhaps it might have something to do with P or rho (or both) being a function of x and y? In the problem the whole pressure term seems to have been grouped with the constant, and I'm wondering if that is justifiable. Beyond that I don't know, it looks like Bernoulli's equation is just not appropriate for this situation for some reason (or else it has been applied incorrectly, but I am not sure why).

I've put this in the homework section, but I should mention that it is not assessed and I am unable to check my answer, so this is just out of interest.
 
Last edited:
Physics news on Phys.org
Hello, jbar18

Bernoulli's equation \frac{P}{\rho} + \frac{u^2}{2} + gz = constant generally holds only along a streamline. The "constant" on the right hand side can be different for different streamlines. Does Bernoulli's equation hold along a steamline for the rotating fluid in the bucket?

[EDIT: Just found this link: Bernoulli’s Equation for a Rotating Fluid ]
 
Last edited:
Hi TSny,

I imagined those streamlines would exist in a plane of constant z. I wondered about the constants, is that the flaw in the logic? Given that this method doesn't work, how might we go about finding the shape of the fluid surface?

Thanks for your reply
 
jbar18 said:
how might we go about finding the shape of the fluid surface?
Thanks for your reply

Look at the derivation of equation (4) in the link and then see how it's applied to the upper surface of the rotating fluid to get equation (6).
 
  • Like
Likes 1 person
Thanks TSny, I'll take a look at that.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top